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AMU MCA Previous Year Questions (PYQs)

AMU MCA Computer Networks PYQ

AMU MCA PYQ
Consider the following terms:

(1) EDGE
(2) Universal Mobile Telecommunication Systems
(3) FHSS
(4) Evolved High Speed Packet Access

Which of the wireless telecommunication systems given above belong to GSM family?






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Solution

Solution:

EDGE → GSM
UMTS → GSM evolution
EHSPA → GSM evolution
FHSS → not GSM

AMU MCA PYQ
Physical topology of FDDI is:






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Solution

FDDI uses dual ring topology.

AMU MCA PYQ
Which one of the following is correct statement?






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Solution

Von-Neumann architecture uses same memory for data and instructions.

AMU MCA PYQ
In network terminology UTP means





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Solution

UTP is the standard copper networking cable.
AMU MCA PYQ
Which one of the following is not a client–server application?





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Solution

Ping uses ICMP and is not a client–server application.
AMU MCA PYQ
Physical topology of FDDI is





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Solution

FDDI uses a dual ring physical topology.
AMU MCA PYQ
Ethernet uses





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Solution

Classic Ethernet is based on bus topology (logical bus).
AMU MCA PYQ
The size of IP address in IPv4 and IPv6 are





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Solution

IPv4 uses 32-bit addresses, IPv6 uses 128-bit addresses.
AMU MCA PYQ
If we need to download text documents at rate of 1000 pages per minute. Each page has 24 lines with 80 characters per line. Find required bit rate.





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Solution

Characters per page = 24 × 80 = 1920 Assume 1 character = 8 bits Bits per page = 1920 × 8 = 15360 bits 1000 pages/min = 15360000 bits/min Bits/sec = 15360000 / 60 = 256000 bps = 0.256 Mbps
AMU MCA PYQ
If every non-key attribute is functionally dependent on primary key, relation is in at least:





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Solution

This condition satisfies 2NF (no partial dependency).
AMU MCA PYQ
QoS stands for





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Solution

QoS in networking means Quality of Service.
AMU MCA PYQ
Consider a noise less channel with bandwidth of 3000 Hz transmitting a signal with two signal levels. Maximum bit rate can be





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Solution

Using Nyquist Formula: $C = 2B \log_2 M$ Here $B = 3000$, $M = 2$ $C = 2 \times 3000 \times \log_2 2$ $= 6000 \times 1$ $= 6000$ bps

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