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UGC NET Computer Science Previous Year Questions (PYQs)

UGC NET Computer Science Digital Logic PYQ


UGC NET Computer Science PYQ
Consider the Boolean expression A(x, y, z) = x (y′ + z′). Which of the following is the complete sum-of-products form of the given Boolean expression?





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UGC NET Computer Science UGC NET PYQ UGC NET Computer Science UGC NET Computer Science 26 June 2025 (Paper II) PYQ

Solution

Given,

A = x (y′ + z′)

= xy′ + xz′

To express as a complete sum-of-products, expand using all variable combinations:

= xy′(z + z′) + xz′(y + y′)

= xy′z + xy′z′ + xyz′ + xy′z′

After simplification, duplicate terms are removed:

A = xyz′ + xy′z + xy′z′


UGC NET Computer Science PYQ
Binary equivalent to $(A0F)_{16}$ is:





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UGC NET Computer Science UGC NET PYQ UGC NET Computer Science UGC NET Computer Science 26 June 2025 (Paper II) PYQ

Solution

A = 1010, 0 = 0000, F = 1111 So, $(A0F){16} = 101000001111{2}$.

UGC NET Computer Science PYQ
Which of the following gates do not give output 1 when both inputs are 0?
A. NAND gate
B. NOR gate
C. XOR gate
D. XNOR gate





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UGC NET Computer Science UGC NET PYQ UGC NET Computer Science UGC NET Computer Science 26 June 2025 (Paper II) PYQ

Solution

Step-by-step explanation:
a = 12, b = 2
a = a + b → a = 14
b = a / b → b = 7
a = a * b → a = 98
b = a - b → b = 91
→ c = 91
Hence, -(*i) = -91
Output: 91 (negative of c printed as -(-91) → 91)

UGC NET Computer Science PYQ
Gray code equivalent to decimal number 8 is:





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UGC NET Computer Science UGC NET PYQ UGC NET Computer Science UGC NET Computer Science 26 June 2025 (Paper II) PYQ

Solution

Binary of 8 = 1000 Gray code is obtained by XORing each bit with the next bit. → MSB remains same. → Remaining bits: perform XOR with the bit to its left. So, $1000 \rightarrow 1100$


UGC NET Computer Science


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UGC NET Computer Science


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