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UGC NET Computer Science Previous Year Questions (PYQs)

UGC NET Computer Science C Programming Language PYQ

UGC NET Computer Science PYQ
int i, j;
for(i = 1; i < 5; i += 2)
    for(j = 1; j < i; j += 2)
        printf("%d", j);





Go to Discussion
UGC NET Computer Science UGC NET PYQ UGC NET Computer Science UGC NET Computer Science 26 June 2025 (Paper II) PYQ

Solution

For i = 1, inner loop condition j < i → 1 < 1 → false → no output.
For i = 3, inner loop runs with j = 1, prints 1, then j = 3 → condition fails.
Hence, final output is 1.
UGC NET Computer Science PYQ
Consider the operators used in C programming given below:
A. &&
B. +=
C. >>
D. >=
E. ?:
Choose among the following the correct order of precedence of the operators given above (higher to lower):





Go to Discussion
UGC NET Computer Science UGC NET PYQ UGC NET Computer Science UGC NET Computer Science 26 June 2025 (Paper II) PYQ

Solution

Operator precedence (highest → lowest) is: >> (shift) → >= (relational) → ?: (ternary) → += (assignment) → && (logical AND).
UGC NET Computer Science PYQ
void main() {
    int *i, a = 12, b = 2, c;
    c = (a = a + b, b = a / b, a = a * b, b = a - b);
    i = &c;
    printf("%d", -(*i));
}






Go to Discussion
UGC NET Computer Science UGC NET PYQ UGC NET Computer Science UGC NET Computer Science 26 June 2025 (Paper II) PYQ

Solution

Step-by-step explanation:
a = 12, b = 2
a = a + b → a = 14
b = a / b → b = 7
a = a * b → a = 98
b = a - b → b = 91
→ c = 91
Hence, -(*i) = -91
Output: 91 (negative of c printed as -(-91) → 91)
UGC NET Computer Science PYQ

int x = 128, y = 110;

do {

    if (x > y) x = x - y;

    else       y = y - x;

} while (x != y);

printf("%d", x);






Go to Discussion
UGC NET Computer Science UGC NET PYQ UGC NET Computer Science UGC NET Computer Science 26 June 2025 (Paper II) PYQ

Solution

Repeated subtraction implements Euclid’s algorithm; the loop ends with x = y = gcd(128,110) = 2.
UGC NET Computer Science PYQ
Only legal pointer operations:
A. pointer + number → pointer
B. pointer – number → number
C. pointer + pointer → pointer
D. pointer – pointer → pointer
E. pointer – pointer → number
Choose the most appropriate answer from the options given below:





Go to Discussion
UGC NET Computer Science UGC NET PYQ UGC NET Computer Science UGC NET Computer Science 26 June 2025 (Paper II) PYQ

Solution

pointer + number → pointer (A)
pointer - pointer → number (E)
UGC NET Computer Science PYQ
What would be the equivalent pointer expression for referring the array element ar[m][n][o]?
  1. *(*(*(ar) + m + n) + o)
  2. (*(*(*(ar + m) + n) + o))
  3. (*(*(ar + m) + n) + o)
  4. *(*(*(ar + m) + n) + o)





Go to Discussion
UGC NET Computer Science UGC NET PYQ UGC NET Computer Science UGC NET Computer Science 26 June 2025 (Paper II) PYQ

Solution

Consider ar as a 3-dimensional array declared as: 

data_type ar[a][b][c];

Here, the array element ar[m][n][o] can be represented in pointer form as: 

*(*(*(ar + m) + n) + o)

Step-by-step understanding:

  • ar is a pointer to the first 2D array ar[0].
  • ar + m moves the pointer to the mth 2D array → ar[m].
  • *(ar + m) gives the address of the first 1D array inside ar[m].
  • *(ar + m) + n moves to the nth 1D array → ar[m][n].
  • *(*(ar + m) + n) gives the address of the first element of that 1D array.
  • *(*(*(ar + m) + n) + o) finally gives the element ar[m][n][o].

✅ Final Answer: *(*(*(ar + m) + n) + o)


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