Qus : 1 NIMCET PYQ 3 Which two of the following numbers comes in the next in the following sequence.
61, 57, 50, 61, 43, 36, 61, ………
1 29, 61 2 29, 20 3 29, 22 4 31, 61 Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2017 PYQ Solution The given series is:
61,57 --- ( -7 )----> 50,61, 43 ---(-7)----> 36, 61, 29 ----(-7)----->22
Thus, following the same pattern next two terms will be 29
and 22.
Qus : 2 NIMCET PYQ 2 In the following sequence, which pair of numbers fill in the blanks?
1, 1, 3, 2, 8, 5, 21, 13, ___, ___
1 54, 33 2 34, 55 3 55, 34 4 33, 54 Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2017 PYQ Solution The Fibonacci Sequence is the series of numbers:
1, 1, 2, 3, 5, 8, 13, 21, 34, 55
Qus : 10 NIMCET PYQ 2
Identify the next two numbers in the following sequence:
17, 20, 9, 12, 5, 6, 3, 2, ____, ____
1 0, 2 2 2, 0 3 1, 2 4 2, 1 Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2023 PYQ Solution
Sequence Question:
Identify the next two numbers in the sequence:
17, 20, 9, 12, 5, 6, 3, 2, ?, ?
Solution:
Let’s split the sequence into two alternate parts:
Odd-positioned terms: 17, 9, 5, 3 → decreasing by 8, 4, 2
Even-positioned terms: 20, 12, 6, 2 → decreasing by 8, 6, 4
Continue the pattern:
Odd series: 17 → 9 (–8), 9 → 5 (–4), 5 → 3 (–2), so next is 3 – 1 = 2
Even series: 20 → 12 (–8), 12 → 6 (–6), 6 → 2 (–4), so next is 2 – 2 = 0
✅ Final Answer:
2, 0
Qus : 13 NIMCET PYQ 2
If 3 is subtracted from the middle digit of each of the following numbers and then the position of the digits are reversed, which of the following will be the last digit of the middle number after they are arranged in descending order?
589 362 554 371 442
1 4 2 3 3 1 4 2 Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2023 PYQ Solution
Digit Puzzle: Final Digit of the Middle Number
Given Numbers: 589, 362, 554, 371, 442
Step 1: Subtract 3 from the middle digit of each number
589 → 58 9 → 55 9 → 559
362 → 36 2 → 33 2 → 332
554 → 55 4 → 52 4 → 524
371 → 37 1 → 34 1 → 341
442 → 44 2 → 41 2 → 412
Step 2: Reverse the digits of each new number
559 → 955
332 → 233
524 → 425
341 → 143
412 → 214
Step 3: Arrange in descending order
955, 425, 233 , 214, 143
Step 4: Pick the middle number
Middle number = 233
Step 5: Find the last digit
Last digit of 233 = 3
✅ Final Answer: 3
Qus : 14 NIMCET PYQ 1
Complete the series: 3,10,24,45,73, ____
1 108 2 121 3 91 4 69 Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2023 PYQ Solution Series: 3, 10, 24, 45, 73, __
Differences:
10−3 = 7
24−10 = 14
45−24 = 21
73−45 = 28
The differences are: 7, 14, 21, 28 → an arithmetic sequence with common difference +7. So the next difference is 35 .
Next term: 73 + 35 = 108
Answer: 108
Qus : 15 NIMCET PYQ 3 If 137+ 276 = 435 , how much is 731 + 672 ?
1 534 2 1403 3 1623 4 1531 Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2019 PYQ Solution
Given rule: Add numbers in the base where 137 + 276 = 435
holds.
Find the base \(b\):
\(137_b = 1b^2 + 3b + 7\)
\(276_b = 2b^2 + 7b + 6\)
Sum \(= 3b^2 + 10b + 13\)
\(435_b = 4b^2 + 3b + 5\)
Equate: \(3b^2 + 10b + 13 = 4b^2 + 3b + 5 \;\Rightarrow\; b^2 - 7b - 8 = 0\)
So \(b = 8\) (since base must be > 7). Thus the operations are in base 8 (octal) .
Now add in base 8: \(731_8 + 672_8\)
731₈
+ 672₈
-------
(units) 1 + 2 = 3 → write 3
(eights) 3 + 7 = 10₁₀ = 12₈ → write 2, carry 1
(sixty-fours) 7 + 6 + 1 = 14₁₀ = 16₈ → write 6, carry 1
bring down carry → 1
-------
1623₈
Answer: \(731 + 672 = \mathbf{1623_8}\) (in base 8).
Qus : 16 NIMCET PYQ 3 Which pair of numbers comes next in the following series? 42 40 38 35 33 31 28
1 25 22 2 26 23 3 26 24 4 25 23 Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2013 PYQ Solution
Series: 42, 40, 38, 35, 33, 31, 28, …
Pattern (differences): −2, −2, −3, −2, −2, −3, … (repeats)
After 28: 28 − 2 = 26 , then 26 − 2 = 24 .
Next pair: 26, 24
Qus : 18 NIMCET PYQ 3 Identify the sixth number in the series:
6, 11, 21, 36, 56, ?
1 52 2 21 3 81 4 82 Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2022 PYQ Solution Series: 6, 11, 21, 36, 56, ?
Differences
11 − 6 = 5
21 − 11 = 10
36 − 21 = 15
56 − 36 = 20
The differences are +5, +10, +15, +20 (increase by 5 each time). Next difference = +25 .
Next term
56 + 25 = 81
Answer: 81
Qus : 20 NIMCET PYQ 1 What pair comes next in the following sequence 99, 90, 83, 78, ...
1 74, 74 2 69, 57 3 67, 59 4 69, 63 Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2019 PYQ Solution Reason: The sequence subtracts consecutive odd numbers decreasing by 2 each step:
99 → 90 : −9
90 → 83 : −7
83 → 78 : −5
78 → 75 : −3 (next odd)
75 → 74 : −1 (next odd)
So after 78, the terms are: 75, 74 .
Qus : 31 NIMCET PYQ 1 Which of the following pairs of number follow the number in the series 2, 4, 12, 24, 72, _____, _____?
1 144, 432 2 288, 332 3 332, 177 4 432, 144 Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2017 PYQ Solution 2 2 x 2 = 4
4 x 3 = 12
12 x 2 = 24
24 x 3 = 72
72 x 2 = 144
144 x 3 = 432
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