If $\alpha $ and $\beta $ be two roots of the equation x2 – 64x + 256 = 0. Then the value of${\left( {{{{\alpha ^3}} \over {{\beta ^5}}}} \right)^{1/8}} + {\left( {{{{\beta ^3}} \over {{\alpha ^5}}}} \right)^{1/8}}$ is :
The value of $\lambda$ such that the sum of the squares of the roots of the quadratic equation
$x^2 + (3 - \lambda)x + 2 = \lambda$
has the least value, is –
The number of integral values of $k$ for which one root of the equation $2x^{2}-8x+k=0$ lies in the interval $(1,2)$ and its other root lies in the interval $(2,3)$ is:
Let $\alpha$ and $\beta$ be the roots of equation $px^{2}+qx+r=0$, $p\ne 0$.
If $p,q,r$ are in A.P. and $\dfrac{1}{\alpha}+\dfrac{1}{\beta}=4$, then the
value of $|\alpha-\beta|$ is :
If $\lambda \in \mathbb{R}$ is such that the sum of the cubes of the roots of the equation $x^{2} + (2-\lambda)x + (10-\lambda)=0$ is minimum, then the magnitude of the difference of the roots of this equation is :
If $\alpha, \beta$ are the roots of the equation
$x^{2} - \left(5 + 3\sqrt{\log_{3}5} - 5\sqrt{\log_{5}3}\right)x + 3\left(3^{\tfrac{1}{3}\log_{3}5} - 5^{\tfrac{2}{3}\log_{5}3} - 1\right) = 0$,
then the equation, whose roots are $\alpha + \tfrac{1}{\beta}$ and $\beta + \tfrac{1}{\alpha}$, is:
Let the set of all values of $p\in\mathbb{R}$, for which both the roots of the equation $x^{2}-(p+2)x+(2p+9)=0$ are negative real numbers, be the interval $(\alpha,\beta)$. Then $\beta-2\alpha$ is:
If the sum of the squares of the reciprocals of the roots $\alpha$ and $\beta$ of the equation 3x2 + $\lambda$x $-$ 1 = 0 is 15, then 6($\alpha$3 + $\beta$3)2 is equal to :
$
\text{Let } \alpha, \beta \text{ be the roots of the equation } x^{2} - \sqrt{2}x + \sqrt{6} = 0
\text{ and } \dfrac{1}{\alpha^{2}} + 1, ; \dfrac{1}{\beta^{2}} + 1 \text{ be the roots of the equation }
x^{2} + ax + b = 0.
$
$\text{Then the roots of the equation } x^{2} - (a+b-2)x + (a+b+2) = 0 \text{ are :}$
If $\lambda$ be the ratio of the roots of the quadratic equation in $x$,
\[
3m^{2}x^{2}+m(m-4)x+2=0,
\]
then the least value of $m$ for which $\displaystyle \lambda+\frac{1}{\lambda}=1$ is:
Let a, b $\in$ R be such that the equation $a{x^2} - 2bx + 15 = 0$ has a repeated root $\alpha$. If $\alpha$ and $\beta$ are the roots of the equation ${x^2} - 2bx + 21 = 0$, then ${\alpha ^2} + {\beta ^2}$ is equal to :
The set of all values of K > $-$1, for which the equation ${(3{x^2} + 4x + 3)^2} - (k + 1)(3{x^2} + 4x + 3)(3{x^2} + 4x + 2) + k{(3{x^2} + 4x + 2)^2} = 0$ has real roots, is :
Let $p, q$ and $r$ be real numbers $(p \ne q,, r \ne 0)$, such that the roots of the equation
$\dfrac{1}{x+p} + \dfrac{1}{x+q} = \dfrac{1}{r}$
are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to:
Let $a,b,c\in \mathbb{R}$. If $f(x)=ax^{2}+bx+c$ is such that $a+b+c=3$ and
$f(x+y)=f(x)+f(y)+xy,\ \forall x,y\in \mathbb{R}$, then $\displaystyle \sum_{n=1}^{10} f(n)$ is equal to :
If for a positive integer $n$, the quadratic equation
$x(x+1) + (x+1)(x+2) + \ldots + (x+n-1)(x+n) = 10n$
has two consecutive integral solutions, then $n$ is equal to :
Let $x=\dfrac{m}{n}$ ($m,n$ are co-prime natural numbers) be a solution of the equation
$\cos\!\left(2\sin^{-1}x\right)=\dfrac{1}{9}$ and let $\alpha,\beta\ (\alpha>\beta)$ be the roots of
the equation $m x^{2}-n x-m+n=0$. Then the point $(\alpha,\beta)$ lies on the line
Let P(x) = x2 + bx + c be a quadratic polynomial with real coefficients such that $\int_0^1 {P(x)dx} $ = 1 and P(x) leaves remainder 5 when it is divided by (x $-$ 2). Then the value of 9(b + c) is equal to :
Let p(x) be a quadratic polynomial such that p(0)=1. If p(x) leaves remainder 4 when divided by x-1 and it leaves remainder 6 when divided by x+1, then:
Let $\alpha, \beta$ be the roots of the quadratic equation $x^{2}+\sqrt{6}x+3=0$. Then $\dfrac{\alpha^{23}+\beta^{23}+\alpha^{14}+\beta^{14}}{\alpha^{15}+\beta^{15}+\alpha^{10}+\beta^{10}}$ is equal to:
Let f(x) be a quadratic polynomial such that f($-$2) + f(3) = 0. If one of the roots of f(x) = 0 is $-$1, then the sum of the roots of f(x) = 0 is equal to :
For $0 < c < b < a$, let
$(a+b-2c)x^{2} + (b+c-2a)x + (c+a-2b) = 0$
and let $\alpha \ne 1$ be one of its roots. Then, among the two statements:
(I) If $\alpha \in (-1,0)$, then $b$ cannot be the geometric mean of $a$ and $c$.
(II) If $\alpha \in (0,1)$, then $b$ may be the geometric mean of $a$ and $c$.
Let $\lambda\ne 0$ be a real number. Let $\alpha,\beta$ be the roots of the equation $14x^{2}-31x+3\lambda=0$ and $\alpha,\gamma$ be the roots of the equation $35x^{2}-53x+4\lambda=0$.
Then $\dfrac{3\alpha}{\beta}$ and $\dfrac{4\alpha}{\gamma}$ are the roots of the equation
Let $\alpha, \beta$ be the roots of the equation
$ x^{2} + 2\sqrt{2}x - 1 = 0 $.
The quadratic equation whose roots are
$\alpha^{4} + \beta^{4}$ and $\dfrac{1}{10} (\alpha^{6} + \beta^{6})$ is:
Let $a$ be the sum of all coefficients in the expansion of
$\big(1-2x+2x^{2}\big)^{2023}\big(3-4x^{2}+2x^{3}\big)^{2024}$
and
$b=\lim_{x\to 0}\left(\frac{\displaystyle \int_{0}^{x}\frac{\log(1+t)}{2t^{2}+t}\,dt}{x^{2}}\right).$
If the equations $c x^{2}+d x+e=0$ and $2b\,x^{2}+a x+4=0$ have a common root,
where $c,d,e\in\mathbb{R}$, then $d:c:e$ equals:
Let $\alpha,\beta;\ \alpha>\beta,$ be the roots of the equation $x^{2}-\sqrt{2},x-\sqrt{3}=0$.
Let $P_{n}=\alpha^{n}-\beta^{n},\ n\in\mathbb{N}$. Then
$(11\sqrt{3}-10\sqrt{2}),P_{10}+(11\sqrt{2}+10),P_{11}-11,P_{12}$ is equal to:
If $m$ is chosen in the quadratic equation
$(m^{2}+1)x^{2}-3x+(m^{2}+1)^{2}=0$
such that the sum of its roots is greatest, then the absolute difference of the cubes of its roots is:
The set of all real values of $\lambda $ for which thequadratic equations, ($\lambda $2 + 1)x2 – 4$\lambda $x + 2 = 0 always have exactly one root in the interval (0, 1) is :
Let $\alpha $ and $\beta $ be the roots of x2 - 3x + p=0 and $\gamma $ and $\delta $ be the roots of x2 - 6x + q = 0. If $\alpha, \beta, \gamma, \delta $form a geometric progression.Then ratio (2q + p) : (2q - p) is:
If $\alpha$ and $\beta$ are the roots of the quadratic equation $x^{2}+x\sin\theta-2\sin\theta=0,\ \theta\in\left(0,\dfrac{\pi}{2}\right)$, then
$\displaystyle \frac{\alpha^{12}+\beta^{12}}{\left(\alpha^{-12}+\beta^{-12}\right)}\cdot(\alpha-\beta)^{24}$ is equal to:
The numbers of pairs (a, b) of real numbers, such that whenever $\alpha$ is a root of the equation x2 + ax + b = 0, $\alpha$2 $-$ 2 is also a root of this equation, is :
Let $\alpha$ and $\beta$ be the roots of $x^2 + \sqrt{3}x - 16 = 0$, and $\gamma$ and $\delta$ be the roots of $x^2 + 3x - 1 = 0$.
If $P_n = \alpha^n + \beta^n$ and $Q_n = \gamma^n + \delta^n$, then
$\dfrac{P_{25} + \sqrt{3}P_{24}}{2P_{23}} + \dfrac{Q_{25} - Q_{23}}{Q_{24}}$
is equal to
Let $\lambda \ne 0$ be in R. If $\alpha $ and $\beta $ are the roots of the equation, x2 - x + 2$\lambda $ = 0 and $\alpha $ and $\gamma $ are the roots of the equation, $3{x^2} - 10x + 27\lambda = 0$, then ${{\beta \gamma } \over \lambda }$ is equal to:
Let \alpha_\theta and \beta_\theta be the distinct roots of $2x^2+(\cos\theta)x-1=0$, $\theta\in(0,2\pi)$. If $m$ and $M$ are the minimum and the maximum values of $\alpha_\theta^{4}+\beta_\theta^{4}$, then $16(M+m)$ equals:
Let $\alpha$ and $\beta$ be the roots of the equation $p x^{2}+q x-r=0$, where $p\ne 0$.
If $p,q,r$ are consecutive terms of a non-constant G.P. and
$\dfrac1\alpha+\dfrac1\beta=\dfrac34$, then the value of $(\alpha-\beta)^{2}$ is:
The number of all possible positive integral values of $\alpha$ for which the roots of the quadratic equation $6x^{2}-11x+\alpha=0$ are rational numbers is:
Consider the equation $x^{2}+4x-n=0$, where $n\in[20,100]$ is a natural number. Then the number of all distinct values of $n$, for which the given equation has integral roots, is equal to
Consider the quadratic equation $(c - 5)x^2 - 2cx + (c - 4) = 0,\ c \ne 5.$
Let $S$ be the set of all integral values of $c$ for which one root of the equation lies in the interval $(0, 2)$ and its other root lies in the interval $(2, 3).$
Then the number of elements in $S$ is:
If $\alpha $ and $\beta $ are the roots of the equation,7x2 – 3x – 2 = 0, then the value of${\alpha \over {1 - {\alpha ^2}}} + {\beta \over {1 - {\beta ^2}}}$ is equal to :