If the first term of an A.P. is $3$ and the sum of its first four terms is equal to one-fifth of the sum of the next four terms, then the sum of the first $20$ terms is:
Let $9=x_{1} < x_{2} < \ldots < x_{7}$ be in an A.P. with common difference d. If the standard deviation of $x_{1}, x_{2}..., x_{7}$ is 4 and the mean is $\bar{x}$, then $\bar{x}+x_{6}$ is equal to :
If $\alpha, \beta$ and $\gamma$ are three consecutive terms of a non-constant G.P. such that the equations
$\alpha x^{2} + 2\beta x + \gamma = 0$ and $x^{2} + x - 1 = 0$
have a common root, then $\alpha(\beta + \gamma)$ is equal to:
If the sum of the first $20$ terms of the series $\dfrac{4\cdot1}{4+3\cdot1^{2}+1^{4}}+\dfrac{4\cdot2}{4+3\cdot2^{2}+2^{4}}+\dfrac{4\cdot3}{4+3\cdot3^{2}+3^{4}}+\dfrac{4\cdot4}{4+3\cdot4^{2}+4^{4}}+\cdots$ is $\dfrac{m}{n}$, where $m$ and $n$ are coprime, then $m+n$ is equal to:
Three positive numbers form an increasing G.P. If the middle term in this G.P.
is doubled, the new numbers are in A.P. then the common ratio of the G.P. is :
If $a,b,c$ are in AP and $a+1,; b,; c+3$ are in GP. Given $a>10$ and the arithmetic mean of $a,b,c$ is $8$, then the cube of the geometric mean of $a,b,c$ is:
Consider two sets $A$ and $B$, each containing three numbers in A.P. Let the sum and the product of the elements of $A$ be $36$ and $p$ respectively and the sum and the product of the elements of $B$ be $36$ and $q$ respectively. Let $d$ and $D$ be the common differences of the A.P.s in $A$ and $B$ respectively such that $D=d+3$, $d>0$. If $\dfrac{p+q}{p-q}=\dfrac{19}{5}$, then $p-q$ is equal to:
The common difference of the A.P. b1, b2, … , bm is 2 more than the common difference of A.P. a1, a2, …, an. If a40 = –159, a100 = –399 andb100 = a70, then b1 is equal to :
$ \text{Suppose } a_1, a_2, \ldots, a_n, \ldots \text{ be an arithmetic progression of natural numbers. If } \dfrac{S_5}{S_9} = \dfrac{5}{17} \text{ and } 110 < a_{15} < 120, \text{ then the sum of the first ten terms of the progression is equal to:} $
If $x_1, x_2,\ldots , x_n$ and $\frac{1}{h_1}, \frac{1}{h_2},\ldots , \frac{1}{h_n}$ are two A.P.s such that
$x_3 = h_2 = 8$ and $x_8 = h_7 = 20$, then $x_5 \cdot h_{10}$ equals :
If $\dfrac{1}{\sqrt{1}+\sqrt{2}}+\dfrac{1}{\sqrt{2}+\sqrt{3}}+\cdots+\dfrac{1}{\sqrt{99}+\sqrt{100}}=m$ and $\dfrac{1}{1\cdot 2}+\dfrac{1}{2\cdot 3}+\cdots+\dfrac{1}{99\cdot 100}=n$, then the point $(m,n)$ lies on the line:
Let the sum of an infinite G.P., whose first term is $a$ and the common ratio is $r$, be $5$. Let the sum of its first five terms be $\dfrac{98}{25}$. Then the sum of the first $21$ terms of an A.P., whose first term is $10ar$, $n^{\text{th}}$ term is $a_n$ and the common difference is $10ar^{2}$, is equal to:
Let $x_1,x_2,x_3,x_4$ be in a geometric progression. If $2,7,9,5$ are subtracted respectively from $x_1,x_2,x_3,x_4$, then the resulting numbers are in an arithmetic progression. Then the value of $\dfrac1{24}(x_1x_2x_3x_4)$ is
If $a$, $b$, $c$ are in A.P. and $a^{2}$, $b^{2}$, $c^{2}$ are in G.P. such that $a < b < c$ and $a + b + c = \dfrac{3}{4}$, then the value of $a$ is :
If $\{ {a_i}\} _{i = 1}^n$, where n is an even integer, is an arithmetic progression with common difference 1, and $\sum\limits_{i = 1}^n {{a_i} = 192} ,\,\sum\limits_{i = 1}^{n/2} {{a_{2i}} = 120} $, then n is equal to :
Let $S_n = \dfrac{1}{2} + \dfrac{1}{6} + \dfrac{1}{12} + \dfrac{1}{20} + \dots$ up to $n$ terms.
If the sum of the first six terms of an A.P. with first term $-p$ and common difference $p$ is $\sqrt{2026}, S_{2025}$, then the absolute difference between $20^{\text{th}}$ and $15^{\text{th}}$ terms of the A.P. is
Let g : N $\to$ N be defined as g(3n + 1) = 3n + 2, g(3n + 2) = 3n + 3, g(3n + 3) = 3n + 1, for all n $\ge$ 0. Then which of the following statements is true?
The number of common terms in the progressions
$4,\,9,\,14,\,19,\ldots,$ up to $25^{\text{th}}$ term and
$3,\,6,\,9,\,12,\ldots,$ up to $37^{\text{th}}$ term is:
If the sum of the second, fourth and sixth terms of a G.P. of positive terms is $21$ and the sum of its eighth, tenth and twelfth terms is $15309$, then the sum of its first nine terms is:
Let $\alpha$ and $\beta$ be the roots of the quadratic equation
$x^{2}\sin\theta-x(\sin\theta\cos\theta+1)+\cos\theta=0$ $(0<\theta<45^\circ)$, and $\alpha<\beta$.
Then $\displaystyle\sum_{n=0}^{\infty}\left(\alpha^{n}+\frac{(-1)^{n}}{\beta^{n}}\right)$ is equal to :
$ \text{Let } S_K=\dfrac{1+2+\cdots+K}{K} \text{ and } \displaystyle\sum_{j=1}^{n} S_j^{2}=\dfrac{n}{A}\big(Bn^{2}+Cn+D\big),\ \text{where } A,B,C,D\in\mathbb{N} \text{ and } A \text{ has least value. Then:} $
If ${1 \over {2\,.\,{3^{10}}}} + {1 \over {{2^2}\,.\,{3^9}}} + \,\,.....\,\, + \,\,{1 \over {{2^{10}}\,.\,3}} = {K \over {{2^{10}}\,.\,{3^{10}}}}$, then the remainder when K is divided by 6 is :
Let $a_1, a_2, a_3, \ldots, a_{49}$ be in A.P. such that
$\displaystyle \sum_{k=0}^{12} a_{4k+1} = 416$ and $a_9 + a_{43} = 66$.
If $a_1^{2} + a_2^{2} + \cdots + a_{17}^{2} = 140m$, then $m$ is equal to :
Let $(a_n)$ be a sequence such that $a_0=0$, $a_1=\dfrac{1}{2}$ and $2a_{n+2}=5a_{n+1}-3a_n,; n=0,1,2,\ldots$. Then $\displaystyle \sum_{k=1}^{100} a_k$ is equal to
Let $\mathrm{T}_{\mathrm{r}}$ be the $\mathrm{r}^{\text {th }}$ term of an A.P. If for some $\mathrm{m}, \mathrm{T}_{\mathrm{m}}=\frac{1}{25}, \mathrm{~T}_{25}=\frac{1}{20}$, and $20 \sum\limits_{\mathrm{r}=1}^{25} \mathrm{~T}_{\mathrm{r}}=13$, then $5 \mathrm{~m} \sum\limits_{\mathrm{r}=\mathrm{m}}^{2 \mathrm{~m}} \mathrm{~T}_{\mathrm{r}}$ is equal to
Let $\alpha,\beta$ be the distinct roots of $x^{2}-(t^{2}-5t+6)x+1=0$, $t\in\mathbb{R}$, and let $a_n=\alpha^{n}+\beta^{n}$. Then the minimum value of $\dfrac{a_{2023}+a_{2025}}{a_{2024}}$ is:
In an increasing geometric series, the sum of the second and the sixth term is ${{25} \over 2}$ and the product of the third and fifth term is 25. Then, the sum of 4th, 6th and 8th terms is equal to :
The product of three consecutive terms of a G.P. is 512. If 4 is added to each of the first and the second of these terms, the three terms now form an A.P. Then the sum of the original three terms of the given G.P. is :
Let $\dfrac{1}{x_1},\dfrac{1}{x_2},\ldots,\dfrac{1}{x_n}$ $(x_i\ne0\text{ for }i=1,2,\ldots,n)$ be in A.P. such that $x_1=4$ and $x_{21}=20$. If $n$ is the least positive integer for which $x_n>50$, then $\displaystyle\sum_{i=1}^n \left(\dfrac{1}{x_i}\right)$ is equal to :
A natural number has prime factorization given by n = 2x3y5z, where y and z are such that y + z = 5 and y$-$1 + z$-$1 = ${5 \over 6}$, y > z. Then the number of odd divisions of n, including 1, is :
The first term $\alpha$ and common ratio $r$ of a geometric progression are positive integers. If the sum of squares of its first three terms is $33033$, then the sum of these three terms is equal to:
Let $ABC$ be an equilateral triangle. A new triangle is formed by joining the midpoints of all sides of $\triangle ABC$, and the same process is repeated infinitely many times. If $P$ is the sum of the perimeters and $Q$ is the sum of the areas of all the triangles formed in this process, then:
A software company sets up $n$ computer systems to finish an assignment in $17$ days. If $4$ systems crash at the start of the second day, $4$ more at the start of the third day, and so on (each day $4$ additional systems crash), then it takes $8$ more days to finish the assignment. The value of $n$ is:
Let $x_1, x_2, \ldots, x_{100}$ be in an arithmetic progression, with $x_1 = 2$ and their mean equal to $200$.
If $y_i = i(x_i - i), \; 1 \le i \le 100$, then the mean of $y_1, y_2, \ldots, y_{100}$ is:
If each term of a geometric progression $a_1,a_2,a_3,\ldots$ with $a_1=\dfrac{1}{8}$ and $a_2\ne a_1$
is the arithmetic mean of the next two terms and $S_n=a_1+a_2+\cdots+a_n$, then $S_{20}-S_{18}$ is equal to
If the sum of first $11$ terms of an A.P.
$a_1, a_2, a_3, \ldots$ is $0 \; (a \neq 0)$,
then the sum of the A.P.
$a_1, a_3, a_5, \ldots, a_{23}$ is $k a_1$, where $k$ is equal to :
Let $a,b$ be distinct positive reals. The $11^{\text{th}}$ term of a GP with first term $a$ and third term $b$ equals the $p^{\text{th}}$ term of another GP with first term $a$ and fifth term $b$. Then $p$ equals:
If three distinct numbers $a,b,c$ are in G.P. and the equations $a x^{2}+2bx+c=0$ and $d x^{2}+2ex+f=0$ have a common root, then which one of the following statements is correct?
If the first term of an A.P. is 3 and the sum of its first 25 terms is equal to the sum of its next 15 terms, then the common difference of this A.P. is :
Let A1, A2, A3, ....... be an increasing geometric progression of positive real numbers. If A1A3A5A7 = ${1 \over {1296}}$ and A2 + A4 = ${7 \over {36}}$, then the value of A6 + A8 + A10 is equal to
Let $s_1,s_2,s_3,\ldots,s_{10}$ respectively be the sum to $12$ terms of $10$ A.P.s whose first terms are $1,2,3,\ldots,10$ and the common differences are $1,3,5,\ldots,19$ respectively. Then $\sum_{i=1}^{10}s_i$ is equal to:
If each term of a geometric progression $a_1,a_2,a_3,\dots$ with $a_1=\dfrac{1}{8}$ and $a_2\neq a_1$ is the arithmetic mean of the next two terms, and $S_n=a_1+a_2+\dots+a_n$, then $S_{20}-S_{18}$ is equal to:
Let $a_1, a_2, a_3, \dots$ be a G.P. of increasing positive numbers. Let the sum of its $6^{th}$ and $8^{th}$ terms be $2$ and the product of its $3^{rd}$ and $5^{th}$ terms be $\dfrac{1}{9}$. Then $6(a_2 + a_4)(a_4 + a_6)$ is equal to
If n arithmetic means are inserted between a and 100 such that the ratio of the first mean to the last mean is 1 : 7 and a + n = 33, then the value of n is :
The sum of the series
$\displaystyle \frac{1}{1-3\cdot1^{2}+1^{4}}+\frac{2}{1-3\cdot2^{2}+2^{4}}+\frac{3}{1-3\cdot3^{2}+3^{4}}+\cdots$
up to $10$ terms is:
Let the sum of the first $n$ terms of a non-constant A.P., $a_1, a_2, a_3, \dots$ be
$50n + \dfrac{n(n - 7)}{2}A$,
where $A$ is a constant. If $d$ is the common difference of this A.P., then the ordered pair $(d, a_{50})$ is equal to
Three numbers are in an increasing geometric progression with common ratio r. If the middle number is doubled, then the new numbers are in an arithmetic progression with common difference d. If the fourth term of GP is 3 r2, then r2 $-$ d is equal to :
Let $a_1, a_2, a_3, \ldots$ be in an A.P. such that
$ \displaystyle \sum_{k=1}^{12} 2a_{2k-1} = -\dfrac{72}{5}a_1, \quad a_1 \ne 0.$
If
$ \displaystyle \sum_{k=1}^{n} a_k = 0, $
then $n$ is:
Let S1 be the sum of first 2n terms of an arithmetic progression. Let S2 be the sum of first 4n terms of the same arithmetic progression. If (S2 $-$ S1) is 1000, then the sum of the first 6n terms of the arithmetic progression is equal to :
Let $a_1, a_2, \ldots, a_{30}$ be an A.P.,
$S = \sum_{i=1}^{30} a_i$ and $T = \sum_{i=1}^{15} a_{(2i-1)}$.
If $a_5 = 27$ and $S - 2T = 75$, then $a_{10}$ is equal to:
Let $A_1$ and $A_2$ be two arithmetic means and $G_1, G_2, G_3$ be three geometric means of two distinct positive numbers. Then $G_1^4+G_2^4+G_3^4+G_1^2G_3^2$ is equal to:
Let $a,ar,ar^{2},\ldots$ be an infinite G.P. If $\displaystyle \sum_{n=0}^{\infty} a r^{n}=57$ and $\displaystyle \sum_{n=0}^{\infty} a^{3} r^{3n}=9747$, then $a+18r$ is equal to:
Let the $2^{\text{nd}}, 8^{\text{th}}$ and $44^{\text{th}}$ terms of a non-constant A.P.
be respectively the $1^{\text{st}}, 2^{\text{nd}}$ and $3^{\text{rd}}$ terms of a G.P.
If the first term of the A.P. is $1$, then the sum of its first $20$ terms is:
The number of terms of an A.P. is even.
The sum of all the odd terms is $24$, the sum of all the even terms is $30$, and the last term exceeds the first by $\dfrac{21}{2}$.
Then the number of terms which are integers in the A.P. is:
Let a1, a2, a3, ..... be an A.P. If ${{{a_1} + {a_2} + .... + {a_{10}}} \over {{a_1} + {a_2} + .... + {a_p}}} = {{100} \over {{p^2}}}$, p $\ne$ 10, then ${{{a_{11}}} \over {{a_{10}}}}$ is equal to :
Let $a_1, a_2, a_3, \ldots$ be a G.P. of increasing positive numbers.
If $a_3 a_5 = 729$ and $a_2 + a_4 = \dfrac{111}{4}$, then $24(a_1 + a_2 + a_3)$ is equal to:
Let a1, a2, ..........., a21 be an AP such that $\sum\limits_{n = 1}^{20} {{1 \over {{a_n}{a_{n + 1}}}} = {4 \over 9}} $. If the sum of this AP is 189, then a6a16 is equal to :
Let $a, b$ and $c$ be the $7^{\text{th}}, 11^{\text{th}}$ and $13^{\text{th}}$ terms respectively of a non-constant A.P. If these are also three consecutive terms of a G.P., then $\dfrac{a}{c}$ is equal to:
Let $a,b,c>1$, $a^{3},b^{3}$ and $c^{3}$ be in A.P., and $\log_{a} b,\ \log_{c} a$ and $\log_{b} c$ be in G.P. If the sum of first $20$ terms of an A.P., whose first term is $\dfrac{a+4b+c}{3}$ and the common difference is $\dfrac{a-8b+c}{10}$, is $-444$, then $abc$ is equal to:
Let $a_{1}, a_{2}, a_{3}, \ldots, a_{n}, \ldots$ be in A.P.
If $a_{3} + a_{7} + a_{11} + a_{15} = 72$, then the sum of its first $17$ terms is equal to:
Let a1, a2, ..., an be a given A.P. whose common difference is an integer and Sn = a1 + a2 + .... + an. If a1 = 1, an = 300 and 15 $ \le $ n $ \le $ 50, then the ordered pair (Sn-4, an–4) is equal to:
If ${3^{2\sin 2\alpha - 1}}$, 14 and ${3^{4 - 2\sin 2\alpha }}$ are the first three terms of an A.P. for some $\alpha $, then the sixthterms of this A.P. is:
If b is very small as compared to the value of a, so that the cube and other higher powers of ${b \over a}$ can be neglected in the identity ${1 \over {a - b}} + {1 \over {a - 2b}} + {1 \over {a - 3b}} + ..... + {1 \over {a - nb}} = \alpha n + \beta {n^2} + \gamma {n^3}$, then the value of $\gamma$ is :
Let $S_n$ denote the sum of the first $n$ terms of an arithmetic progression.
If $S_{10} = 390$ and the ratio of the tenth and the fifth terms is $15 : 7$, then $S_{15} - S_{5}$ is equal to:
If $\alpha$ and $\beta$ are the roots of the equation $375x^2 - 25x - 2 = 0$, then
$\displaystyle \lim_{n \to \infty} \sum_{r=1}^{n} \alpha^r + \lim_{n \to \infty} \sum_{r=1}^{n} \beta^r$
is equal to:
Let $\alpha$ and $\beta$ be the roots of equation $x^{2}-6x-2=0$.
If $a_{n}=\alpha^{n}-\beta^{n}$, for $n\ge 1$, then the value of $\dfrac{a_{10}-2a_{8}}{2a_{9}}$ is equal to :
Suppose that the number of terms in an A.P. is $2k$, $k\in\mathbb{N}$. If the sum of all odd terms of the A.P. is $40$, the sum of all even terms is $55$ and the last term exceeds the first term by $27$, then $k$ is equal to:
If the sum of the second, third and fourth terms of a positive term G.P. is 3 and the sum of its sixth, seventh and eighth terms is 243, then the sum of the first 50 terms of this G.P. is :
Consider two G.P.s: $2, 2^{2}, 2^{3}, \ldots$ (of $60$ terms) and $4, 4^{2}, 4^{3}, \ldots$ (of $n$ terms).
If the geometric mean of all the $60+n$ terms is $(2)^{\tfrac{225}{8}}$, then $\displaystyle \sum_{k=1}^{n} k(n-k)$ is equal to:
If $m$ is the A.M. of two distinct real numbers $l$ and $n$ $(l,n>1)$ and
$G_{1},G_{2}$ and $G_{3}$ are three geometric means between $l$ and $n$, then
$G_{1}^{4}+2G_{2}^{4}+G_{3}^{4}$ equals :
Let the first three terms $2,\,p,\,q$ with $q\ne 2$ of a G.P. be respectively the $7^{\text{th}},\,8^{\text{th}}$ and $13^{\text{th}}$ terms of an A.P.
If the $5^{\text{th}}$ term of the G.P. is the $n^{\text{th}}$ term of the A.P., then $n$ is equal to: