Consider a hyperbola $\text{H}$ having centre at the origin and foci on the x-axis.
Let $C_1$ be the circle touching the hyperbola $\text{H}$ and having the centre at the origin.
Let $C_2$ be the circle touching the hyperbola $\text{H}$ at its vertex and having the centre at one of its foci.
If areas (in sq units) of $C_1$ and $C_2$ are $36\pi$ and $4\pi$, respectively,
then the length (in units) of latus rectum of $\text{H}$ is:
Let the matrix $A=\left[\begin{array}{lll}1 & 0 & 0 \\ 1 & 0 & 1 \\ 0 & 1 & 0\end{array}\right]$ satisfy $A^n=A^{n-2}+A^2-I$ for $n \geqslant 3$. Then the sum of all the elements of $\mathrm{A}^{50}$ is :
If the vertices of a hyperbola are at $(-2,0)$ and $(2,0)$ and one of its foci is at $(-3,0)$, then which one of the following points does not lie on this hyperbola?
Let $H:\dfrac{-x^2}{a^2}+\dfrac{y^2}{b^2}=1$ be the hyperbola whose eccentricity is $\sqrt{3}$ and the length of the latus rectum is $4\sqrt{3}$.
Suppose the point $(\alpha,6)$, $\alpha>0$, lies on $H$.
If $\beta$ is the product of the focal distances of the point $(\alpha,6)$, then $\alpha^2+\beta$ is equal to:
A hyperbola having the transverse axis of length $\sqrt 2 $ has the same foci as that of the ellipse 3x2 + 4y2 = 12, then this hyperbola does notpass through which of the following points?
Let $P$ be a point on the hyperbola $H:\ \dfrac{x^2}{9}-\dfrac{y^2}{4}=1$, in the first quadrant, such that the area of the triangle formed by $P$ and the two foci of $H$ is $2\sqrt{13}$. Then, the square of the distance of $P$ from the origin is:
Let $T$ and $C$ respectively be the transverse and conjugate axes of the hyperbola
$16x^{2}-y^{2}+64x+4y+44=0$.
Then the area of the region above the parabola $x^{2}=y+4$, below the transverse axis $T$ and on the right of the conjugate axis $C$ is:
Let one focus of the hyperbola $\textbf{H}: \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1$ be at $(\sqrt{10}, 0)$ and the corresponding directrix be $x = \dfrac{9}{\sqrt{10}}$.
If $e$ and $l$ respectively are the eccentricity and the length of the latus rectum of $\textbf{H}$, then $9(e^2 + l)$ is equal to:
Let a > 0, b > 0. Let e and l respectively be the eccentricity and length of the latus rectum of the hyperbola ${{{x^2}} \over {{a^2}}} - {{{y^2}} \over {{b^2}}} = 1$. Let e' and l' respectively be the eccentricity and length of the latus rectum of its conjugate hyperbola. If ${e^2} = {{11} \over {14}}l$ and ${\left( {e'} \right)^2} = {{11} \over 8}l'$, then the value of $77a + 44b$ is equal to :
Let the foci of a hyperbola $H$ coincide with the foci of the ellipse
$\displaystyle E:\ \frac{(x-1)^{2}}{100}+\frac{(y-1)^{2}}{75}=1$
and the eccentricity of the hyperbola $H$ be the reciprocal of the eccentricity of the ellipse $E$. If the length of the transverse axis of $H$ is $\alpha$ and the length of its conjugate axis is $\beta$, then $3\alpha^{2}+2\beta^{2}$ is equal to:
Let e1 and e2 be the eccentricities of theellipse, ${{{x^2}} \over {25}} + {{{y^2}} \over {{b^2}}} = 1$(b < 5) and the hyperbola, ${{{x^2}} \over {16}} - {{{y^2}} \over {{b^2}}} = 1$ respectively satisfying e1e2 = 1. If $\alpha $ and $\beta $ are the distances between the foci of the ellipse and the foci of the hyperbola respectively, then the ordered pair ($\alpha $, $\beta $) is equal to :
The eccentricity of the hyperbola whose length of the latus rectum is equal to $8$ and the length of its conjugate axis is equal to half of the distance between its foci, is:
Let $0<\theta<\frac{\pi}{2}$. If the eccentricity of the hyperbola
$\dfrac{x^2}{\cos^2\theta}-\dfrac{y^2}{\sin^2\theta}=1$ is greater than $2$, then the length of its latus rectum lies in the interval:
Let $a$ and $b$ respectively be the semitransverse and semi-conjugate axes of a hyperbola whose eccentricity satisfies the equation $9e^{2} - 18e + 5 = 0$. If $S(5,0)$ is a focus and $5x = 9$ is the corresponding directrix of this hyperbola, then $a^{2} - b^{2}$ is equal to :
A hyperbola has its centre at the origin, passes through the point $(4,2)$ and has transverse axis of length $4$ along the $x$-axis. Then the eccentricity of the hyperbola is:
If a directrix of a hyperbola centred at the origin and passing through the point $(4,-2\sqrt{3})$ is $5x=4\sqrt{5}$ and its eccentricity is $e$, then:
Let the foci of the ellipse $\dfrac{x^{2}}{16}+\dfrac{y^{2}}{7}=1$ and the hyperbola $\dfrac{x^{2}}{144}-\dfrac{y^{2}}{\alpha}=\dfrac{1}{25}$ coincide. Then the length of the latus rectum of the hyperbola is :