Let $S={(\lambda,\mu)\in\mathbb{R}\times\mathbb{R}: f(t)=(\lvert\lambda\rvert e^{\lvert t\rvert}-\mu)\cdot\sin(2\lvert t\rvert),\ t\in\mathbb{R},\text{ is a differentiable function}}$. Then $S$ is a subset of :
Let $K$ be the set of all real values of $x$ where the function $f(x)=\sin|x|-|x|+2(x-\pi)\cos|x|$ is not differentiable. Then the set $K$ is equal to:
Let $S$ be the set of all points in $(-\pi,\pi)$ at which the function
$f(x)=\min\{\sin x,\cos x\}$ is not differentiable. Then $S$ is a subset of which of the following?
$ \text{The number of points where the function } f:\mathbb{R}\to\mathbb{R},\quad
f(x)=|x-1|\cos|x-2|\sin|x-1|+(x-3),|x^{2}-5x+4|,\ \text{is NOT differentiable, is:} $
Let f, g : R $\to$ R be two real valued functions defined as $f(x) = \left\{ {\matrix{ { - |x + 3|} & , & {x < 0} \cr {{e^x}} & , & {x \ge 0} \cr } } \right.$ and $g(x) = \left\{ {\matrix{ {{x^2} + {k_1}x} & , & {x < 0} \cr {4x + {k_2}} & , & {x \ge 0} \cr } } \right.$, where k1 and k2 are real constants. If (gof) is differentiable at x = 0, then (gof) ($-$ 4) + (gof) (4) is equal to :
Let the functions f : R $ \to $ R and g : R $ \to $ R be defined as :$f(x) = \left\{ {\matrix{ {x + 2,} & {x < 0} \cr {{x^2},} & {x \ge 0} \cr } } \right.$ and $g(x) = \left\{ {\matrix{ {{x^3},} & {x < 1} \cr {3x - 2,} & {x \ge 1} \cr } } \right.$ Then, the number of points in R where (fog) (x) is NOT differentiable is equal to :
Let f(x) = min {1, 1 + x sin x}, 0 $\le$ x $\le$ 2$\pi $. If m is the number of points, where f is not differentiable and n is the number of points, where f is not continuous, then the ordered pair (m, n) is equal to
If $f(x) = \left\{ {\matrix{ {{1 \over {|x|}}} & {;\,|x|\, \ge 1} \cr {a{x^2} + b} & {;\,|x|\, < 1} \cr } } \right.$ is differentiable at every point of the domain, then the values of a and b are respectively :
Let $g(x)$ be a linear function and
$
f(x)=
\begin{cases}
g(x), & x\le 0,\\[2mm]
\left(\dfrac{1+x}{2+x}\right)^{\tfrac{1}{x}}, & x>0
\end{cases}
$
is continuous at $x=0$. If $f'(1)=f(-1)$, then the value $g(3)$ is
where [t] is the greatest integer less than or equal to t. Let m be the number of points where f is not differentiable and $I = \int\limits_{ - 2}^2 {f(x)\,dx} $. Then the ordered pair (m, I) is equal to :
Let $[x]$ denote the greatest integer function and
$f(x)=\max\{\,1+x+[x],\ 2+x,\ x+2[x]\,\},\ 0\le x\le 2.$
Let $m$ be the number of points in $[0,2]$, where $f$ is not continuous and $n$ be the number of points in $(0,2)$, where $f$ is not differentiable. Then $(m+n)^2+2$ is equal to:
Consider the function $f:(0,\infty)\to\mathbb{R}$ defined by
$f(x)=e^{-|\log_e x|}$. If $m$ and $n$ are respectively the number of points at
which $f$ is not continuous and $f$ is not differentiable, then $m+n$ is:
Let $f$ be a differentiable function from $\mathbb{R}$ to $\mathbb{R}$ such that $|f(x)-f(y)|\le 2|x-y|^{3/2}$ for all $x,y\in\mathbb{R}$. If $f(0)=1$, then $\displaystyle \int_{0}^{1} f^{2}(x)\,dx$ is equal to:
Let $f(x)=\left|2x^{2}+5|x|-3\right|,\; x\in\mathbb{R}$.
If $m$ and $n$ denote the number of points where $f$ is not continuous and not differentiable respectively,
then $m+n$ is equal to: