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JEE MAIN Previous Year Questions (PYQs)

JEE MAIN Differential Equation PYQ


JEE MAIN PYQ
Let the population of rabbits surviving at time $t$ be governed by the differential equation $\dfrac{dp(t)}{dt}=\dfrac{1}{2}p(t)-200$. If $p(0)=100$, then $p(t)$ equals:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2014 (Offline) PYQ

Solution


JEE MAIN PYQ
The curve amongst the family of curves represented by the differential equation $(x^2 - y^2)dx + 2xy\,dy = 0$ which passes through $(1, 1)$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (10 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area enclosed by the closed curve $\mathcal{C}$ given by the differential equation $\dfrac{dy}{dx}+\dfrac{x+a}{\,y-2\,}=0,\quad y(1)=0$ is $4\pi$. Let $P$ and $Q$ be the points of intersection of the curve $\mathcal{C}$ with the $y$-axis. If the normals at $P$ and $Q$ on $\mathcal{C}$ intersect the $x$-axis at points $R$ and $S$ respectively, then the length of the line segment $RS$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (1 February Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be the solution of the differential equation xdy = (y + x3 cosx)dx with y($\pi$) = 0, then $y\left( {{\pi \over 2}} \right)$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (25 July Evening Shift) PYQ

Solution


JEE MAIN PYQ
If $y=y(x)$ is the solution curve of the differential equation $\dfrac{dy}{dx}+y\tan x=x\sec x,\ 0\le x\le \dfrac{\pi}{3},\ y(0)=1$, then $y\!\left(\dfrac{\pi}{6}\right)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (1 February Morning Shift) PYQ

Solution


JEE MAIN PYQ
The general solution of the differential equation (y2 – x3)dx – xydy = 0 (x $ \ne $ 0) is : (where c is a constant of integration)





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (12 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
If a curve $y=y(x)$ passes through the point $\left(1,\dfrac{\pi}{2}\right)$ and satisfies the differential equation $(7x^{4}\cot y-e^{x}\csc y),\dfrac{dx}{dy}=x^{5},\ x\ge1$, then at $x=2$, the value of $\cos y$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (4 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let the solution curve $y=f(x)$ of the differential equation $\dfrac{dy}{dx}+\dfrac{xy}{x^{2}-1}=\dfrac{x^{4}+2x}{\sqrt{1-x^{2}}}$, $x\in(-1,1)$, pass through the origin. Then $\displaystyle \int_{-\sqrt{3}/2}^{\sqrt{3}/2} f(x)\,dx$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (26 July Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution of the differential equation $(x^{2}+4)^{2}\,dy+(2x^{3}y+8xy-2)\,dx=0.$ If $y(0)=0$, then $y(2)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (4 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be solution of the differential equation ${\log _{}}\left( {{{dy} \over {dx}}} \right) = 3x + 4y$, with y(0) = 0.If $y\left( { - {2 \over 3}{{\log }_e}2} \right) = \alpha {\log _e}2$, then the value of $\alpha$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (27 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
For all twice differentiable functions f : R $ \to $ R,with f(0) = f(1) = f'(0) = 0





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 6 September 2020 (Evening) PYQ

Solution


JEE MAIN PYQ
Let $\alpha x = \exp(x^{\beta} y^{\gamma})$ be the solution of the differential equation $2x^{2}y\,dy - (1 - xy^{2})\,dx = 0,\ x>0,\ y(2)=\sqrt{\log_{e}2}.$ Then $\alpha + \beta - \gamma$ equals:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (1 February Evening Shift) PYQ

Solution


JEE MAIN PYQ
At present, a firm is manufacturing $2000$ items. It is estimated that the rate of change of production $P$ w.r.t. additional number of workers $x$ is given by $\dfrac{dP}{dx}=100-12\sqrt{x}$. If the firm employs $25$ more workers, then the new level of production of items is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2013 (Offline) PYQ

Solution


JEE MAIN PYQ
Let $x=x(y)$ be the solution of the differential equation $y=\left(x-y \frac{\mathrm{~d} x}{\mathrm{~d} y}\right) \sin \left(\frac{x}{y}\right), y>0$ and $x(1)=\frac{\pi}{2}$. Then $\cos (x(2))$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (23 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $y = y_{1}(x)$ and $y = y_{2}(x)$ be two distinct solutions of the differential equation $\dfrac{dy}{dx} = x + y$, with $y_{1}(0) = 0$ and $y_{2}(0) = 1$ respectively. Then, the number of points of intersection of $y = y_{1}(x)$ and $y = y_{2}(x)$ is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (27 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
If $y(x)$ is the solution of the differential equation $\dfrac{dy}{dx}+\left(\dfrac{2x+1}{x}\right)y=e^{-2x},\ x>0,$ where $y(1)=\dfrac{1}{2}e^{-2}$, then





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (11 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution curve of the differential equation $x(x^{2}+e^{x})^{2}dy+\big(e^{x}(x-2)y-x^{3}\big)dx=0, x>0,$ passing through the point $(1,0)$. Then $y(2)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (7 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be the solution of the differential equation ${{dy} \over {dx}} + 2y = f\left( x \right),$

where $f\left( x \right) = \left\{ {\matrix{ {1,} & {x \in \left[ {0,1} \right]} \cr {0,} & {otherwise} \cr } } \right.$

If y(0) = 0, then $y\left( {{3 \over 2}} \right)$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2018 (15 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be a solution curve of the differential equation $(y + 1){\tan ^2}x\,dx + \tan x\,dy + y\,dx = 0$, $x \in \left( {0,{\pi \over 2}} \right)$. If $\mathop {\lim }\limits_{x \to 0 + } xy(x) = 1$, then the value of $y\left( {{\pi \over 4}} \right)$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (26 August Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $x=x(t)$ and $y=y(t)$ be solutions of the differential equations $\dfrac{dx}{dt}+ax=0$ and $\dfrac{dy}{dt}+by=0$ respectively, $a,b\in\mathbb{R}$. Given that $x(0)=2$, $y(0)=1$ and $3y(1)=2x(1)$, the value of $t$ for which $x(t)=y(t)$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (27 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y = y(x)$ be the solution of the differential equation $\left(xy - 5x^2\sqrt{1 + x^2}\right)dx + (1 + x^2)dy = 0$, $y(0) = 0$. Then $y(\sqrt{3})$ is equal to





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (24 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
If the solution curve $f(x,y)=0$ of the differential equation $(1+\log_e x)\frac{dx}{dy}-x\log_e x=e^y,\; x>0,$ passes through the points $(1,0)$ and $(\alpha,2)$, then $\alpha^\alpha$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (6 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
If $y=y(x)$ solves the differential equation $\dfrac{dy}{dx}+2y=\sin(2x)$ with $y(0)=\dfrac{3}{4}$, then $y!\left(\dfrac{\pi}{8}\right)$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (5 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution of the differential equation $(x^{2}+1),y'-2xy=(x^{4}+2x^{2}+1)\cos x$, with $y(0)=1$. Then $\displaystyle \int_{-3}^{3} y(x),dx$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (7 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let the solution curve of the differential equation $x,dy = \left(\sqrt{x^{2}+y^{2}}+y\right)dx,; x>0,$ intersect the line $x=1$ at $y=0$ and the line $x=2$ at $y=\alpha$. Then the value of $\alpha$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (28 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
If x = x(y) is the solution of the differential equation $y{{dx} \over {dy}} = 2x + {y^3}(y + 1){e^y},\,x(1) = 0$; then x(e) is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (24 June Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let y(x) be the solution of the differential equation 2x2 dy + (ey $-$ 2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (26 August Evening Shift) PYQ

Solution


JEE MAIN PYQ
. If $y(\theta)=\dfrac{2\cos\theta+\cos2\theta}{\cos3\theta+\cos2\theta+5\cos\theta+2}$, then at $\theta=\dfrac{\pi}{2}$, the value of $y''+y'+y$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (5 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
If $y=y(x),\; x\in(0,\pi/2)$ be the solution curve of the differential equation $$(\sin^{2}2x)\dfrac{dy}{dx}+(8\sin^{2}2x+2\sin 4x)y=2e^{-4x}(2\sin 2x+\cos 2x),$$ with $y(\pi/4)=e^{-\pi}$, then $y(\pi/6)$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (28 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
The curve satisfying the differential equation $(x^{2}-y^{2}),dx + 2xy,dy = 0$ and passing through the point $(1,1)$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2018 (15 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
$ \text{Let } C(\alpha,\beta) \text{ be the circumcenter of the triangle formed by the lines } 4x+3y=69,; 4y-3x=17,; x+7y=61. $ $ \text{Then } (\alpha-\beta)^2+\alpha+\beta \text{ is equal to:} $





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (8 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The minimum value of the twice differentiable function $f(x)=\int_{0}^{x} e^{,x-t},f'(t),dt-(x^{2}-x+1)e^{x},; x\in\mathbb{R}$, is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (28 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
he solution of the differential equation, $\dfrac{dy}{dx}=(x-y)^{2}$, when $y(1)=1$, is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (11 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
The differential equation of the family of circles passing through the origin and having centre on the line $y=x$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (5 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
If $y=y(x)$ is the solution curve of the differential equation $(x^2-4)\,dy-(y^2-3y)\,dx=0,\ x>2,\ y(4)=\dfrac{3}{2}$ and the slope of the curve is never zero, then the value of $y(10)$ equals:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (27 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
$ \text{Let } y=y(x) \text{ be the solution curve of the differential equation } \dfrac{dy}{dx}+\dfrac{1}{x^{2}-1},y=\left(\dfrac{x-1}{x+1}\right)^{1/2},; x>1,\ \text{passing through the point } \left(2,\sqrt{\tfrac{1}{3}}\right). \text{ Then } \sqrt{7},y(8) \text{ is equal to:} $





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (28 July Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $f:(0,\infty)\to\mathbb{R}$ be a function which is differentiable at all points of its domain and satisfies the condition $x^2 f'(x)=2x f(x)+3$, with $f(1)=4$. Then $2f(2)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (24 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $g:(0,\infty ) \to R$ be a differentiable function such that $\int {\left( {{{x(\cos x - \sin x)} \over {{e^x} + 1}} + {{g(x)\left( {{e^x} + 1 - x{e^x}} \right)} \over {{{({e^x} + 1)}^2}}}} \right)dx = {{x\,g(x)} \over {{e^x} + 1}} + c} $, for all x > 0, where c is an arbitrary constant. Then :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (25 June Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y = y(x)$ be the solution of the differential equation $(x + 1)y' - y = {e^{3x}}{(x + 1)^2}$, with $y(0) = {1 \over 3}$. Then, the point $x = - {4 \over 3}$ for the curve $y = y(x)$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (25 June Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y = y(x)$ be the solution of the differential equation $\sin x \dfrac{dy}{dx} + y \cos x = 4x,\ x \in (0,\pi).$ If $y\left(\dfrac{\pi}{2}\right) = 0$, then $y\left(\dfrac{\pi}{6}\right)$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2018 (Offline) PYQ

Solution


JEE MAIN PYQ
If the solution curve $y = y(x)$ of the differential equation ${y^2}dx + ({x^2} - xy + {y^2})dy = 0$, which passes through the point (1, 1) and intersects the line $y = \sqrt 3 x$ at the point $(\alpha ,\sqrt 3 \alpha )$, then value of ${\log _e}(\sqrt 3 \alpha )$ is equal to :






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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (25 June Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let the solution curve $y = y(x)$ of the differential equation $\left(1 + e^{2x}\right)\left(\dfrac{dy}{dx} + y\right) = 1$ pass through the point $\left(0, \dfrac{\pi}{2}\right)$. Then, $\lim_{x \to \infty} e^x y(x)$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (29 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
$ \text{Let the solution curve } y=y(x) \text{ of the differential equation } (1+e^{2x})!\left(\dfrac{dy}{dx}+y\right)=1 \text{ pass through the point } \left(0,\dfrac{\pi}{2}\right). $ $ \text{Then } \lim_{x\to\infty} e^{x}y(x) \text{ is equal to:} $





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (29 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ solve $(2x\log_e x),\dfrac{dy}{dx}+2y=\dfrac{3}{x}\log_e x$ for $x>0$ with $y(e^{-1})=0$. Then $y(e)$ equals:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (6 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
If $y = y(x)$ is the solution of the differential equation $2{x^2}{{dy} \over {dx}} - 2xy + 3{y^2} = 0$ such that $y(e) = {e \over 3}$, then y(1) is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (25 June Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ solve the differential equation $(1+x^{2})\dfrac{dy}{dx}+y=e^{\tan^{-1}x}$ with $y(1)=0$. Then $y(0)$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (6 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The function $f$ is differentiable and satisfies $x^{2}f(x)-x=4\displaystyle\int_{0}^{x} t f(t),dt$, with $f(1)=\dfrac{2}{3}$. Then $18f(3)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (10 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
If a curve passes through the point $(1, -2)$ and has slope of the tangent at any point $(x, y)$ on it as $\dfrac{x^2 - 2y}{x}$, then the curve also passes through the point:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (12 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $f(x) = \int\limits_0^x {{e^t}f(t)dt + {e^x}} $ be a differentiable function for all x$\in$R. Then f(x) equals :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (26 February Evening Shift) PYQ

Solution


JEE MAIN PYQ
A function $y=f(x)$ satisfies $f(x)\sin 2x+\sin x-(1+\cos^2x)\,f'(x)=0$ with condition $f(0)=0$. Then $f\!\left(\dfrac{\pi}{2}\right)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (29 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
If the solution curve of the differential equation $ \dfrac{dy}{dx}=\dfrac{x+y-2}{x-y} $ passes through the points $(2,1)$ and $(k+1,2)$, $k>0$, then





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (29 July Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution curve of the differential equation $ \frac{dy}{dx}+\left(\frac{2x^{2}+11x+13}{x^{3}+6x^{2}+11x+6}\right)y=\frac{x+3}{x+1},\quad x>-1, $ which passes through the point $(0,1)$. Then $y(1)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (29 July Evening Shift) PYQ

Solution


JEE MAIN PYQ
Suppose the solution of the differential equation $ \displaystyle \frac{dy}{dx}=\frac{(2+\alpha)x-\beta y+2}{\beta x-2\alpha y-(\beta\gamma-4\alpha)} $ represents a circle passing through the origin. Then the radius of this circle is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (6 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $y = y(x)$ be a solution curve of the differential equation \[ (1 - x^2 y^2)\,dx = y\,dx + x\,dy. \] If the line $x = 1$ intersects the curve $y = y(x)$ at $y = 2$ and the line $x = 2$ intersects the curve $y = y(x)$ at $y = \alpha$, then a value of $\alpha$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (11 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $f(x)=x-1$ and $g(x)=e^x$ for $x\in\mathbb{R}$. If $\dfrac{dy}{dx}=e^{-2\sqrt{x}}g\big(f(f(x))\big)-\dfrac{y}{\sqrt{x}}, y(0)=0$, then $y(1)$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (8 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $y = y(x)$ be the solution of the differential equation $\dfrac{2 + \sin x}{y+1} \cdot \dfrac{dy}{dx} = -\cos x,\; y > 0,\; y(0) = 1.$ If $y(\pi) = a$ and $\dfrac{dy}{dx}$ at $x = \pi$ is $b$, then the ordered pair $(a,b)$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2 September 2020 (Morning) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution of the differential equation $x^{3}\,dy+(xy-1)\,dx=0,\quad x>0,$ with $y\!\left(\dfrac{1}{2}\right)=3-e.$ Then $y(1)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (24 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
If $y = y(x)$ is the solution of the differential equation $x{{dy} \over {dx}} + 2y = x\,{e^x}$, $y(1) = 0$ then the local maximum value of the function $z(x) = {x^2}y(x) - {e^x},\,x \in R$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (26 June Evening Shift) PYQ

Solution


JEE MAIN PYQ
If y = y(x) is the solution of the differential equation, ${{dy} \over {dx}} + 2y\tan x = \sin x,y\left( {{\pi \over 3}} \right) = 0$, then the maximum value of the function y(x) over R is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (16 March Morning Shift) PYQ

Solution


JEE MAIN PYQ
f the solution of the differential equation ${{dy} \over {dx}} + {e^x}\left( {{x^2} - 2} \right)y = \left( {{x^2} - 2x} \right)\left( {{x^2} - 2} \right){e^{2x}}$ satisfies $y(0) = 0$, then the value of y(2) is _______________.





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (26 June Evening Shift) PYQ

Solution


JEE MAIN PYQ
If y = y(x) is the solution of the differential equation ${{dy} \over {dx}}$ + (tan x) y = sin x, $0 \le x \le {\pi \over 3}$, with y(0) = 0, then $y\left( {{\pi \over 4}} \right)$ equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (16 March Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $f(x)$ be a positive function such that the area bounded by $y=f(x)$, $y=0$ from $x=0$ to $x=a>0$ is $e^{-a}+4a^{2}+a-1$. Then the differential equation whose general solution is $y=c_1f(x)+c_2$, where $c_1$ and $c_2$ are arbitrary constants, is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (8 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
If $(2+\sin x)\dfrac{dy}{dx}+(y+1)\cos x=0$ and $y(0)=1$, then $y\left(\dfrac{\pi}{2}\right)$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2017 (Offline) PYQ

Solution


JEE MAIN PYQ
Consider the integral $I = \int_0^{10} {{{[x]{e^{[x]}}} \over {{e^{x - 1}}}}dx} $, where [x] denotes the greatest integer less than or equal to x. Then the value of I is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (16 March Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution of the differential equation $(1+y^{2})e^{\tan x},dx+\cos^{2}x,(1+e^{2\tan x}),dy=0$, $y(0)=1$. Then $y!\left(\tfrac{\pi}{4}\right)$ is equal to





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (8 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
If a curve y = f(x), passing through the point(1, 2), is the solution of the differential equation,
2x2dy= (2xy + y2)dx, then $f\left( {{1 \over 2}} \right)$ is equal to





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2 September 2020 (Evening) PYQ

Solution


JEE MAIN PYQ
Let A = {2, 3, 4, 5, ....., 30} and '$ \simeq $' be an equivalence relation on A $\times$ A, defined by (a, b) $ \simeq $ (c, d), if and only if ad = bc. Then the number of ordered pairs which satisfy this equivalence relation with ordered pair (4, 3) is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (16 March Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution of the differential equation $(x^2+1)^2\dfrac{dy}{dx}+2x(x^2+1)y=1$ such that $y(0)=0$. If $\sqrt{a,y(1)}=\dfrac{\pi}{32}$, then the value of $a$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (8 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution of the differential equation $(x^{2}-3y^{2})\,dx+3xy\,dy=0$, with $y(1)=1$. Then $6y^{2}(e)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (24 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
If ${{dy} \over {dx}} + {{{2^{x - y}}({2^y} - 1)} \over {{2^x} - 1}} = 0$, x, y > 0, y(1) = 1, then y(2) is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (27 June Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution of the differential equation $\sec x,dy+{2(1-x)\tan x+x(2-x)},dx=0$ with $y(0)=2$. Then $y(2)$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (30 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution of the differential equation \[ \frac{dy}{dx}+\frac{5}{x(x^5+1)}\,y=\frac{(x^5+1)^2}{x^7},\quad x>0. \] If $y(1)=2$, then $y(2)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (11 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
The solution curve of the differential equation, (1 + e-x)(1 + y2)${{dy} \over {dx}}$ = y2, which passes throughthe point (0, 1), is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 3 September 2020 (Morning) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution curve of the differential equation $\sec y,\dfrac{dy}{dx}+2x\sin y=x^{3}\cos y$, with $y(1)=0$. Then $y(\sqrt{3})$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (8 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
Which of the following is true for y(x) that satisfies the differential equation ${{dy} \over {dx}}$ = xy $-$ 1 + x $-$ y; y(0) = 0 :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (17 March Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x),\ y>0$, be a solution curve of the differential equation \[ (1+x^2)\,dy = y(x-y)\,dx. \] If $y(0)=1$ and $y(2\sqrt{2})=\beta$, then





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (12 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
A function $y=f(x)$ satisfies $f(x) \sin 2 x+\sin x-\left(1+\cos ^2 x\right) f^{\prime}(x)=0$ with condition $f(0)=0$. Then, $f\left(\frac{\pi}{2}\right)$ is equal to





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (29 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
If the solution curve of the differential equation $(({\tan ^{ - 1}}y) - x)dy = (1 + {y^2})dx$ passes through the point (1, 0), then the abscissa of the point on the curve whose ordinate is tan(1), is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (27 June Evening Shift) PYQ

Solution


JEE MAIN PYQ
The curve satisfying the differential equation $y,dx-(x+3y^{2}),dy=0$ and passing through the point (1,1), also passes through the point :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2017 (8 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution curve of the differential equation $\displaystyle \frac{dy}{dx}=\frac{y}{x}\bigl(1+xy^{2}(1+\log_{e}x)\bigr),\ x>0,\ y(1)=3.$ Then $\displaystyle \frac{y^{2}(x)}{9}$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (25 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The population P = P(t) at time 't' of a certain species follows the differential equation ${{dP} \over {dt}}$ = 0.5P – 450. If P(0) = 850, then the time at which population becomes zero is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (24 February Morning Shift) PYQ

Solution


JEE MAIN PYQ
If the curve y = y(x) is the solution of the differential equation $2({x^2} + {x^{5/4}})dy - y(x + {x^{1/4}})dx = {2x^{9/4}}dx$, x > 0 which passes through the point $\left( {1,1 - {4 \over 3}{{\log }_e}2} \right)$, then the value of y(16) is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (17 March Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y_1(x)$ and $y=y_2(x)$ be the solution curves of the differential equation $\dfrac{dy}{dx}=y+7$ with initial conditions $y_1(0)=0$ and $y_2(0)=1$ respectively. Then the curves $y=y_1(x)$ and $y=y_2(x)$ intersect at:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (13 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
If $\sin\left(\dfrac{y}{x}\right)=\log_e|x|+\dfrac{\alpha}{x}$ is a solution of the differential equation $x\cos\left(\dfrac{y}{x}\right)\dfrac{dy}{dx}=y\cos\left(\dfrac{y}{x}\right)+x$ with $y(1)=\dfrac{\pi}{3}$, then $\alpha^2$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (29 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let the solution curve $y = y(x)$ of the differential equation

$\left[ {{x \over {\sqrt {{x^2} - {y^2}} }} + {e^{{y \over x}}}} \right]x{{dy} \over {dx}} = x + \left[ {{x \over {\sqrt {{x^2} - {y^2}} }} + {e^{{y \over x}}}} \right]y$

pass through the points (1, 0) and (2$\alpha$, $\alpha$), $\alpha$ > 0. Then $\alpha$ is equal to






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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (28 June Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be the solution of the differential equation $\cos x(3\sin x + \cos x + 3)dy = (1 + y\sin x(3\sin x + \cos x + 3))dx,0 \le x \le {\pi \over 2},y(0) = 0$. Then, $y\left( {{\pi \over 3}} \right)$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (17 March Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be the solution of the differential equation $x(1 - {x^2}){{dy} \over {dx}} + (3{x^2}y - y - 4{x^3}) = 0$, $x > 1$, with $y(2) = - 2$. Then y(3) is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (28 June Morning Shift) PYQ

Solution


JEE MAIN PYQ
The solution of the differential equation $(x^{2}+y^{2}),dx-5xy,dy=0,; y(1)=0,$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (9 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(t)$ be a solution of the differential equation $\dfrac{dy}{dt}+\alpha y=\gamma e^{-\beta t}$ where $\alpha>0$, $\beta>0$ and $\gamma>0$. Then $\displaystyle \lim_{t\to\infty} y(t)$





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (25 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
If $2x = y^{\tfrac{1}{5}} + y^{-\tfrac{1}{5}}$ and $(x^{2} - 1)\dfrac{d^{2}y}{dx^{2}} + \lambda x\dfrac{dy}{dx} + ky = 0$, then $\lambda + k$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2017 (9 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
Three rotten apples are accidentally mixed with fifteen good apples. Assuming the random variable $x$ to be the number of rotten apples in a draw of two apples, the variance of $x$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (31 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The solution curve of the differential equation $2y\dfrac{dy}{dx}+3=5\dfrac{dy}{dx}$, passing through the point $(0,1)$, is a conic whose vertex lies on the line:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (9 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let x = x(y) be the solution of the differential equation $2y\,{e^{x/{y^2}}}dx + \left( {{y^2} - 4x{e^{x/{y^2}}}} \right)dy = 0$ such that x(1) = 0. Then, x(e) is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (28 June Evening Shift) PYQ

Solution


JEE MAIN PYQ
The solution of the differential equation $x\dfrac{dy}{dx} + 2y = x^2 \ (x \ne 0)$ with $y(1) = 1$, is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (9 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let the slope of the tangent to a curve y = f(x) at (x, y) be given by 2 $\tan x(\cos x - y)$. If the curve passes through the point $\left( {{\pi \over 4},0} \right)$, then the value of $\int\limits_0^{\pi /2} {y\,dx} $ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (28 June Evening Shift) PYQ

Solution


JEE MAIN PYQ
The solution curve of the differential equation $y\dfrac{dx}{dy}=x(\log_e x-\log_e y+1),\ x>0,\ y>0,$ passing through the point $(e,1)$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (31 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $\displaystyle \int_{0}^{x}\sqrt{1-\big(y'(t)\big)^{2}},dt=\int_{0}^{x}y(t),dt,\ 0\le x\le 3,\ y\ge0,\ y(0)=0$. Then at $x=2$, $,y''+y+1$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (9 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
If $\cos x{{dy} \over {dx}} - y\sin x = 6x$, (0 < x < ${\pi \over 2}$)
and $y\left( {{\pi \over 3}} \right)$ = 0 then $y\left( {{\pi \over 6}} \right)$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (9 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
If a curve $y = f(x)$ passes through the point $(1,-1)$ and satisfies the differential equation $ y(1+xy),dx = x,dy $, then $ f\left(-\dfrac{1}{2}\right) $ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2016 (Offline) PYQ

Solution


JEE MAIN PYQ
Let $x=x(y)$ be the solution of the differential equation $2(y+2)\log_e(y+2)\,dx+\big(x+4-2\log_e(y+2)\big)\,dy=0,\quad y>-1$ with $x\big(e^{4}-2\big)=1$. Then $x\big(e^{9}-2\big)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (15 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
If ${{dy} \over {dx}} = {{{2^{x + y}} - {2^x}} \over {{2^y}}}$, y(0) = 1, then y(1) is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (31 August Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let the solution curve of the differential equation

$x{{dy} \over {dx}} - y = \sqrt {{y^2} + 16{x^2}} $, $y(1) = 3$ be $y = y(x)$. Then y(2) is equal to:






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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (29 June Morning Shift) PYQ

Solution


JEE MAIN PYQ
If $\log_{e} y = 3\sin^{-1}x$, then $,(1-x^{2})y''-xy',$ at $x=\dfrac{1}{2}$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (9 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $f:[1, \infty) \rightarrow[2, \infty)$ be a differentiable function. If $10 \int_1^1 f(\mathrm{t}) \mathrm{dt}=5 x f(x)-x^5-9$ for all $x \geqslant 1$, then the value of $f(3)$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (2 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution of the differential equation $$x\log_e x \,\frac{dy}{dx}+y=x^2\log_e x,\quad (x>1).$$ If $y(2)=2$, then $y(e)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (29 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
If x3dy + xy dx = x2dy + 2y dx; y(2) = e and x > 1, then y(4) is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 3 September 2020 (Evening) PYQ

Solution


JEE MAIN PYQ
If ${{dy} \over {dx}} = {{{2^x}y + {2^y}{{.2}^x}} \over {{2^x} + {2^{x + y}}{{\log }_e}2}}$, y(0) = 0, then for y = 1, the value of x lies in the interval :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (31 August Evening Shift) PYQ

Solution


JEE MAIN PYQ
If $y{{dy} \over {dx}} = x\left[ {{{{y^2}} \over {{x^2}}} + {{\phi \left( {{{{y^2}} \over {{x^2}}}} \right)} \over {\phi '\left( {{{{y^2}} \over {{x^2}}}} \right)}}} \right]$, x > 0, $\phi$ > 0, and y(1) = $-$1, then $\phi \left( {{{{y^2}} \over 4}} \right)$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (31 August Evening Shift) PYQ

Solution


JEE MAIN PYQ
The temperature $T(t)$ of a body at time $t=0$ is $160^\circ\!F$ and it decreases continuously as per the differential equation $\dfrac{dT}{dt}=-K(T-80)$, where $K$ is a positive constant. If $T(15)=120^\circ\!F$, then $T(45)$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (31 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be the solution of the differential equation $x\tan \left( {{y \over x}} \right)dy = \left( {y\tan \left( {{y \over x}} \right) - x} \right)dx$, $ - 1 \le x \le 1$, $y\left( {{1 \over 2}} \right) = {\pi \over 6}$. Then the area of the region bounded by the curves x = 0, $x = {1 \over {\sqrt 2 }}$ and y = y(x) in the upper half plane is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (20 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
If $y=y(x)$ is the solution of the differential equation $x\dfrac{dy}{dx}+2y=x^{2}$, satisfying $y(1)=1$, then $y\!\left(\dfrac{1}{2}\right)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (9 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be the solution of the differential equation ${e^x}\sqrt {1 - {y^2}} dx + \left( {{y \over x}} \right)dy = 0$, y(1) = $-$1. Then the value of (y(3))2 is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (20 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let the solution curve $y=y(x)$ of the differential equation \[ \frac{dy}{dx}=\frac{3x^5\tan^{-1}(x^3)}{(1+x^6)^{3/2}}\, y = 2x \exp\left\{\frac{x^3-\tan^{-1}(x^3)}{\sqrt{1+x^6}}\right\} \] pass through the origin. Then $y(1)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (30 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
If $y=y(x)$ is the solution of the differential equation $\dfrac{dy}{dx}=(\tan x-y)\sec^{2}x,\ x\in\left(-\dfrac{\pi}{2},\dfrac{\pi}{2}\right)$, such that $y(0)=0$, then $y!\left(-\dfrac{\pi}{4}\right)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (10 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
If y = y(x) is the solution of the differential equation $\left( {1 + {e^{2x}}} \right){{dy} \over {dx}} + 2\left( {1 + {y^2}} \right){e^x} = 0$ and y (0) = 0, then $6\left( {y'(0) + {{\left( {y\left( {{{\log }_e}\sqrt 3 } \right)} \right)}^2}} \right)$ is equal to





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (29 June Evening Shift) PYQ

Solution


JEE MAIN PYQ
If y = y(x) is the solution curve of the differential equation ${x^2}dy + \left( {y - {1 \over x}} \right)dx = 0$ ; x > 0 and y(1) = 1, then $y\left( {{1 \over 2}} \right)$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (1 September Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be the solution of the differential equation,
xy'- y = x2(xcosx + sinx), x > 0. if y ($\pi $) = $\pi $ then
$y''\left( {{\pi \over 2}} \right) + y\left( {{\pi \over 2}} \right)$ is equal to :





Go to Discussion

JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 4 September 2020 (Morning) PYQ

Solution


JEE MAIN PYQ
Let $x=x(y)$ be the solution of the differential equation $y^2\,dx+\left(x-\dfrac{1}{y}\right)dy=0$. If $x(1)=1$, then $x\!\left(\dfrac{1}{2}\right)$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (22 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $g$ be a differentiable function such that $\displaystyle \int_0^x g(t),dt = x - \int_0^x t g(t),dt,; x \ge 0$ and let $y = y(x)$ satisfy the differential equation $\dfrac{dy}{dx} - y \tan x = 2(x + 1)\sec x, g(x),; x \in \left[0, \dfrac{\pi}{2}\right).$ If $y(0) = 0$, then $y\left(\dfrac{\pi}{3}\right)$ is equal to





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (3 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y = y(x)$ be the solution of the differential equation $\frac{dy}{dx} = 2x(x+y)^3 - x(x+y) - 1, \quad y(0) = 1.$ Then, $\left(\dfrac{1}{\sqrt{2}} + y\!\left(\dfrac{1}{\sqrt{2}}\right)\right)^2$ equals :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (1 February Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be the solution of the differential equation $\cos e{c^2}xdy + 2dx = (1 + y\cos 2x)\cos e{c^2}xdx$, with $y\left( {{\pi \over 4}} \right) = 0$. Then, the value of ${(y(0) + 1)^2}$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (22 July Evening Shift) PYQ

Solution


JEE MAIN PYQ
The solution of the differential equation $\dfrac{dy}{dx}=-\left(\dfrac{x^{2}+3y^{2}}{3x^{2}+y^{2}}\right),\ y(1)=0$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (30 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
For $x \in \mathbb{R},\ x \ne 0$, if $y(x)$ is a differentiable function such that $x \int_{1}^{x} y(t)\,dt = (x+1) \int_{1}^{x} t\,y(t)\,dt,$ then $y(x)$ equals: (where $C$ is a constant.)





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2016 (10 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The general solution of the differential equation $(x - y^2),dx + y(5x + y^2),dy = 0$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (25 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $y=y(x)$ be the solution of the differential equation $\dfrac{dy}{dx}+y\tan x=2x+x^{2}\tan x,\ x\in\left(-\dfrac{\pi}{2},\dfrac{\pi}{2}\right)$, such that $y(0)=1$. Then:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (10 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
If $x=f(y)$ is the solution of the differential equation $(1+y^{2})+\big(x-2e^{\tan^{-1}y}\big)\dfrac{dy}{dx}=0,\ y\in\left(-\dfrac{\pi}{2},\dfrac{\pi}{2}\right)$ with $f(0)=1$, then $f\!\left(\dfrac{1}{\sqrt{3}}\right)$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (22 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $\alpha$ be a non-zero real number. Suppose $f:\mathbf{R}\to\mathbf{R}$ is a differentiable function such that $f(0)=2$ and $\displaystyle \lim_{x\to -\infty} f(x)=1$. If $f'(x)=\alpha f(x)+3$, for all $x\in\mathbf{R}$, then $f(-\log_{e}2)$ is equal to:





Go to Discussion

JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (1 February Evening Shift) PYQ

Solution


JEE MAIN PYQ
If y = y(x) is the solution of the differential equation ${{5 + {e^x}} \over {2 + y}}.{{dy} \over {dx}} + {e^x} = 0$ satisfyingy(0) = 1, then a value of y(loge13) is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 5 September 2020 (Morning) PYQ

Solution


JEE MAIN PYQ
Let $f:[0,1]\to\mathbb{R}$ be such that $f(xy)=f(x)\,f(y)$ for all $x,y\in[0,1]$, and $f(0)\ne 0$. If $y=v(x)$ satisfies the differential equation $\dfrac{dy}{dx}=f(x)$ with $y(0)=1$, then $y\!\left(\dfrac{1}{4}\right)+y\!\left(\dfrac{3}{4}\right)$ is equal to:





Go to Discussion

JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (9 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be the solution of the differential equation ${{dy} \over {dx}} = 1 + x{e^{y - x}}, - \sqrt 2 < x < \sqrt 2 ,y(0) = 0$ then, the minimum value of $y(x),x \in \left( { - \sqrt 2 ,\sqrt 2 } \right)$ is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (25 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let y = y(x) be the solution of the differentialequationcosx${{dy} \over {dx}}$ + 2ysinx = sin2x, x $ \in $ $\left( {0,{\pi \over 2}} \right)$.Ify$\left( {{\pi \over 3}} \right)$ = 0, then y$\left( {{\pi \over 4}} \right)$ is equal to :





Go to Discussion

JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 5 September 2020 (Evening) PYQ

Solution


JEE MAIN PYQ
Let $y(x)$ be the solution of the differential equation $(x\log x)\dfrac{dy}{dx}+y=2x\log x,\;(x\ge 1).$ Then $y(e)$ is equal to :





Go to Discussion

JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2015 (Offline) PYQ

Solution


JEE MAIN PYQ
Let a curve $y=f(x)$ pass through the points $(0,5)$ and $(\log_e 2,\,k)$. If the curve satisfies the differential equation $2(3+y)e^{2x}\,dx-(7+e^{2x})\,dy=0$, then $k$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (23 January Morning Shift) PYQ

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JEE MAIN PYQ
Let $y=y(x)$ be the solution of the differential equation $(3y^{2}-5x^{2})\,y\,dx+2x\,(x^{2}-y^{2})\,dy=0$ such that $y(1)=1$. Then $\left|(y(2))^{3}-12y(2)\right|$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (31 January Evening Shift) PYQ

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JEE MAIN PYQ
Let $f:[0,\infty)\to\mathbb{R}$ be a differentiable function such that $f(x)=1-2x+\displaystyle\int_{0}^{x}e^{,x-t}f(t),dt$ for all $x\in[0,\infty)$. Then the area of the region bounded by $y=f(x)$ and the coordinate axes is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (4 April Morning Shift) PYQ

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JEE MAIN PYQ
If the solution $y = y(x)$ of the differential equation $(x^{4}+2x^{3}+3x^{2}+2x+2)\,dy-(2x^{2}+2x+3)\,dx=0$ satisfies $y(-1)=-\dfrac{\pi}{4}$, then $y(0)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (4 April Morning Shift) PYQ

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JEE MAIN PYQ
If \(\dfrac{dy}{dx}+\dfrac{3}{\cos^2 x}\,y=\dfrac{1}{\cos^2 x},\ x\in\left(-\dfrac{\pi}{3},\dfrac{\pi}{3}\right)\) and \(y\!\left(\dfrac{\pi}{4}\right)=\dfrac{4}{3}\), then \(y\!\left(-\dfrac{\pi}{4}\right)\) equals:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (10 January Morning Shift) PYQ

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JEE MAIN PYQ
Let $f(x)= \begin{cases} x^{3}-x^{2}+10x-7, & x\le 1,\\ -2x+\log_{2}(b^{2}-4), & x>1. \end{cases}$ Then the set of all values of $b$ for which $f(x)$ has maximum value at $x=1$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (26 July Morning Shift) PYQ

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JEE MAIN PYQ
The general solution of the differential equation$\sqrt {1 + {x^2} + {y^2} + {x^2}{y^2}} $ + xy${{dy} \over {dx}}$ = 0 is : (where C is a constant of integration)





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 6 September 2020 (Morning) PYQ

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JEE MAIN PYQ
Let $f$ be a differentiable function such that $f'(x) = 7 - \dfrac{3}{4}\,\dfrac{f(x)}{x}$, for $x>0$, and $f(1)\neq 4$. Then $\displaystyle \lim_{x\to 0} x\,f\!\left(\dfrac{1}{x}\right)$ equals:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (10 January Evening Shift) PYQ

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JEE MAIN PYQ
Consider the differential equation $y^{2},dx+\left(x-\dfrac{1}{y}\right)dy=0.$ If $y=1$ when $x=1$, then the value of $x$ for which $y=2$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (12 April Morning Shift) PYQ

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JEE MAIN


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