The region represented by {z = x + iy $ \in $ C : |z| – Re(z) $ \le $ 1} is also given by the inequality :{z = x + iy $ \in $ C : |z| – Re(z) $ \le $ 1}
Let $\alpha$ and $\beta$ be the sum and the product of all the non-zero solutions of the equation
$(\overline{z})^2 + |z| = 0,\; z \in \mathbb{C}$.
Then $4(\alpha^2 + \beta^2)$ is equal to:
Let $z = \left(\dfrac{\sqrt{3}}{2} + \dfrac{i}{2}\right)^5 + \left(\dfrac{\sqrt{3}}{2} - \dfrac{i}{2}\right)^5.$
If $R(z)$ and $I(z)$ respectively denote the real and imaginary parts of $z$, then :
Let C be the set of all complex numbers. Let ${S_1} = \{ z \in C||z - 3 - 2i{|^2} = 8\} $ ${S_2} = \{ z \in C|{\mathop{\rm Re}\nolimits} (z) \ge 5\} $ and ${S_3} = \{ z \in C||z - \overline z | \ge 8\} $. Then the number of elements in ${S_1} \cap {S_2} \cap {S_3}$ is equal to :
Let the product of $\omega_1=(8+i)\sin\theta+(7+4i)\cos\theta$ and $\omega_2=(1+8i)\sin\theta+(4+7i)\cos\theta$ be $\alpha+i\beta$, where $i=\sqrt{-1}$. Let $p$ and $q$ be the maximum and the minimum values of $\alpha+\beta$ respectively. Then $p+q$ is equal to:
Let $a,b$ be two real numbers such that $ab<0$. If the complex number $\dfrac{1+ai}{\,b+i\,}$ is of unit modulus and $a+ib$ lies on the circle $|z-1|=|2z|$, then a possible value of $\dfrac{1+[a]}{4b}$, where $[\,\cdot\,]$ is the greatest integer function, is:
The area (in sq. units) of the region
$S = \{\, z \in \mathbb{C} : |z - 1| \le 2,\ (z + \bar{z}) + i(z - \bar{z}) \le 2,\ \operatorname{Im}(z) \ge 0 \,\}$
is :
$ \text{Let } f,g : \mathbb{N} - \{1\} \to \mathbb{N} \text{ be functions defined by } f(a) = \alpha, \text{ where } \alpha \text{ is the maximum of the powers of those primes } p \text{ such that } p^\alpha \text{ divides } a, \text{ and } g(a) = a+1, \text{ for all } a \in \mathbb{N} - \{1\}. \text{ Then, the function } f+g \text{ is} $
Consider the following two statements:
Statement I: For any two non-zero complex numbers $z_1,z_2$,
$(|z_1|+|z_2|)\left|\dfrac{z_1}{|z_1|}+\dfrac{z_2}{|z_2|}\right|\le 2(|z_1|+|z_2|)$.
Statement II: If $x,y,z$ are three distinct complex numbers and $a,b,c$ are positive real numbers such that $\dfrac{a}{|,y-z,|}=\dfrac{b}{|,z-x,|}=\dfrac{c}{|,x-y,|}$, then
$\dfrac{a^{2}}{,y-z,}+\dfrac{b^{2}}{,z-x,}+\dfrac{c^{2}}{,x-y,}=1$.
Between the above two statements:
The set of all $\alpha \in \mathbb{R}$ for which $w = \dfrac{1 + (1-8\alpha)z}{1-z}$ is purely imaginary number, for all $z \in \mathbb{C}$ satisfying $|z| = 1$ and $\operatorname{Re} z \ne 1$, is :
Among the statements
(S1): The set ${z\in\mathbb{C}\setminus{-i}:\ |z|=1\ \text{ and }\ \dfrac{z-i}{z+i}\ \text{is purely real}}$ contains exactly two elements and
(S2): The set ${z\in\mathbb{C}\setminus{-1}:\ |z|=1\ \text{ and }\ \dfrac{z-1}{z+1}\ \text{is purely imaginary}}$ contains infinitely many elements.
If $\alpha$ and $\beta$ are the roots of the equation $2x^2 - 3x - 2i = 0$, where $i = \sqrt{-1}$, then
$16 \cdot \text{Re}\left( \dfrac{\alpha^{19} + \beta^{19} + \alpha^{11} + \beta^{11}}{\alpha^5 + \beta^5} \right) \cdot \text{Im}\left( \dfrac{\alpha^{19} + \beta^{19} + \alpha^{11} + \beta^{11}}{\alpha^5 + \beta^5} \right)$
is equal to
Let $a\ne b$ be two non-zero real numbers. Then the number of elements in the set
$X=\{\, z\in\mathbb{C} : \operatorname{Re}(a z^{2}+bz)=a \text{ and } \operatorname{Re}(b z^{2}+a z)=b \,\}$ is equal to:
Among the statements:
(S1): $2023^{2022}-1999^{2022}$ is divisible by $8$.
(S2): $13(13)^n-12n-13$ is divisible by $144$ for infinitely many $n\in\mathbb{N}$.
If the locus of $z\in\mathbb{C}$, such that $\operatorname{Re}!\left(\dfrac{z-1}{2z+i}\right)+\operatorname{Re}!\left(\dfrac{z-1}{2z-i}\right)=2$, is a circle of radius $r$ and center $(a,b)$, then $\dfrac{15ab}{r^2}$ is equal to:
Let $S_1=\{z \in \mathbf{C}:|z| \leq 5\}, S_2=\left\{z \in \mathbf{C}: \operatorname{Im}\left(\frac{z+1-\sqrt{3} i}{1-\sqrt{3} i}\right) \geq 0\right\}$ and $S_3=\{z \in \mathbf{C}: \operatorname{Re}(z) \geq 0\}$. Then the area of the region $S_1 \cap S_2 \cap S_3$ is :
If $\alpha$, $\beta$ $\in$ R are such that 1 $-$ 2i (here i2 = $-$1) is a root of z2 + $\alpha$z + $\beta$ = 0, then ($\alpha$ $-$ $\beta$) is equal to :
Let $A=\left\{\theta \in(0,2 \pi): \frac{1+2 i \sin \theta}{1-i \sin \theta}\right.$ is purely imaginary $\}$. Then the sum of the elements in $\mathrm{A}$ is :
Let a circle C in complex plane pass through the points ${z_1} = 3 + 4i$, ${z_2} = 4 + 3i$ and ${z_3} = 5i$. If $z( \ne {z_1})$ is a point on C such that the line through z and z1 is perpendicular to the line through z2 and z3, then $arg(z)$ is equal to :
Let z1 and z2 be two complex numbers such that ${\overline z _1} = i{\overline z _2}$ and $\arg \left( {{{{z_1}} \over {{{\overline z }_2}}}} \right) = \pi $. Then :
Let $O$ be the origin, the point $A$ be $z_1=\sqrt{3}+2\sqrt{2},i$, the point $B$ $(z_2)$ be such that $\sqrt{3},|z_2|=|z_1|$ and $\arg(z_2)=\arg(z_1)+\dfrac{\pi}{6}$. Then
Let $S=\{\,z=x+iy:\ |z-1+i|\ge |z|,\ |z|<2,\ |z+i|=|z-1|\,\}$.
Then the set of all values of $x$, for which $w=2x+iy\in S$ for some $y\in\mathbb{R}$, is:
Let a complex number z, |z| $\ne$ 1, satisfy ${\log _{{1 \over {\sqrt 2 }}}}\left( {{{|z| + 11} \over {{{(|z| - 1)}^2}}}} \right) \le 2$. Then, the largest value of |z| is equal to ____________.
If $\alpha + i\beta$ and $\gamma + i\delta$ are the roots of $x^2 - (3 - 2i)x - (2i - 2) = 0$, $i = \sqrt{-1}$, then $\alpha \gamma + \beta \delta$ is equal to:
Let $p, q \in \mathbb{R}$ and $(1 - \sqrt{3}i)^{200} = 2^{199}(p + iq),\ i = \sqrt{-1}$
Then $p + q + q^2$ and $p - q + q^2$ are roots of the equation.
Let $w_1$ be the point obtained by the rotation of $z_1 = 5 + 4i$ about the origin through a right angle in the anticlockwise direction,
and $w_2$ be the point obtained by the rotation of $z_2 = 3 + 5i$ about the origin through a right angle in the clockwise direction.
Then the principal argument of $w_1 - w_2$ is equal to:
Let $r$ and $\theta$ respectively be the modulus and amplitude of the complex number
$z=2-i\!\left(2\tan\frac{5\pi}{8}\right)$. Then $(r,\theta)$ is equal to:
For $a \in \mathbb{C}$, let
$A = \{\, z \in \mathbb{C} : \Re(a + \bar z) > \Im(\bar a + z) \,\}$
and
$B = \{\, z \in \mathbb{C} : \Re(a + \bar z) < \Im(\bar a + z) \,\}$.
Then among the two statements:
(S1): If $\Re(a), \Im(a) > 0$, then the set $A$ contains all the real numbers.
(S2): If $\Re(a), \Im(a) < 0$, then the set $B$ contains all the real numbers.
The least value of |z| where z is complex number which satisfies the inequality $\exp \left( {{{(|z| + 3)(|z| - 1)} \over {||z| + 1|}}{{\log }_e}2} \right) \ge {\log _{\sqrt 2 }}|5\sqrt 7 + 9i|,i = \sqrt { - 1} $, is equal to :
Let $z$ be a complex number such that $\lvert z+2\rvert=1$ and $\operatorname{Im}!\left(\dfrac{z+1}{z+2}\right)=\dfrac{1}{5}$. Then the value of $\lvert \operatorname{Re}(z+2)\rvert$ is
If the set $R=\{(a, b): a+5 b=42, a, b \in \mathbb{N}\}$ has $m$ elements and $\sum_\limits{n=1}^m\left(1-i^{n !}\right)=x+i y$, where $i=\sqrt{-1}$, then the value of $m+x+y$ is
If $z = \dfrac{1}{2} - 2i$ is such that $|z + 1| = \alpha z + \beta (1 + i)$, $i = \sqrt{-1}$ and $\alpha, \beta \in \mathbb{R}$,
then $\alpha + \beta$ is equal to:
Let $C$ be the circle in the complex plane with centre $z_0=\tfrac{1}{2}(1+3i)$ and radius $r=1$.
Let $z_1=1+i$ and the complex number $z_2$ be outside the circle $C$ such that
$\lvert z_1-z_0\rvert\,\lvert z_2-z_0\rvert=1$.
If $z_0,z_1$ and $z_2$ are collinear, then the smaller value of $\lvert z_2\rvert^2$ is equal to:
Let $S_1, S_2$ and $S_3$ be three sets defined as
$S_1 = \{z \in C : |z - 1| \le \sqrt{2}\}$
,$S_2 = \{z \in C : \text{Re}((1 - i)z) \ge 1\}$
$S_3 = \{z \in C : \text{Im}(z) \le 1\}$
Then the set $S_1 \cap S_2 \cap S_3$
The equation
$\operatorname{Im}\left( \dfrac{iz - 2}{z - i} \right) + 1 = 0,; z \in \mathbb{C},; z \neq i$
represents a part of a circle having radius equal to:
Let $r$ and $\theta$ respectively be the modulus and amplitude of the complex number
$z = 2 - i\left(2\tan\dfrac{5\pi}{8}\right)$,
then $(r, \theta)$ is equal to:
If the equation $a|z{|^2} + \overline {\overline \alpha z + \alpha \overline z } + d = 0$ represents a circle where a, d are real constants then which of the following condition is correct?
Let $z$ be a complex number such that $|z| = 1$.
If $\dfrac{2 + k\bar{z}}{k + z} = kz$, $k \in \mathbb{R}$, then the maximum distance of $k + ik^2$ from the circle $|z - (1 + 2i)| = 1$ is:
For two non-zero complex numbers $z_{1}$ and $z_{2}$, if $\operatorname{Re}(z_{1}z_{2})=0$ and $\operatorname{Re}(z_{1}+z_{2})=0$, then which of the following are possible?
A. $\operatorname{Im}(z_{1})>0$ and $\operatorname{Im}(z_{2})>0$
B. $\operatorname{Im}(z_{1})<0$ and $\operatorname{Im}(z_{2})>0$
C. $\operatorname{Im}(z_{1})>0$ and $\operatorname{Im}(z_{2})<0$
D. $\operatorname{Im}(z_{1})<0$ and $\operatorname{Im}(z_{2})<0$
Choose the correct answer from the options given below:
Let $z$ be a complex number such that the real part of $\displaystyle \frac{z-2i}{z+2i}$ is zero. Then, the maximum value of $\lvert z-(6+8i)\rvert$ is:
Let a complex number be w = 1 $-$ ${\sqrt 3 }$i. Let another complex number z be such that |zw| = 1 and arg(z) $-$ arg(w) = ${\pi \over 2}$. Then the area of the triangle with vertices origin, z and w is equal to :
If $\alpha$ and $\beta$ are the distinct roots of the equation ${x^2} + {(3)^{1/4}}x + {3^{1/2}} = 0$, then the value of ${\alpha ^{96}}({\alpha ^{12}} - 1) + {\beta ^{96}}({\beta ^{12}} - 1)$ is equal to :
If the set $\left\{\operatorname{Re}\!\left(\dfrac{z-\overline{z}+z\overline{z}}{\,2-3z+5\overline{z}\,}\right): z\in\mathbb{C},\ \operatorname{Re}(z)=3\right\}$ is equal to the interval $(\alpha,\beta]$, then $24(\beta-\alpha)$ is equal to:
The point represented by $2 + i$ in the Argand plane moves $1$ unit eastwards, then $2$ units northwards and finally from there $2\sqrt{2}$ units in the south-westwards direction. Then its new position in the Argand plane is at the point represented by:
Let $u = {{2z + i} \over {z - ki}}$, z = x + iy and k > 0. If the curve represented by Re(u) + Im(u) = 1 intersects the y-axis at the points P and Q where PQ = 5, then the value of k is :
Let $S=\left\{\,z\in\mathbb{C}:\ |z-1|=1 \ \text{and}\
\left|(\sqrt2-1)(z+\bar z)-i(z-\bar z)\right|=2\sqrt2\,\right\}$.
Let $z_1,z_2\in S$ be such that $|z_1|=\max_{z\in S}|z|$ and $|z_2|=\min_{z\in S}|z|$.
Then $\ \left|\sqrt2\,z_1-z_2\right|^{2}$ equals:
If the real part of the complex number ${(1 - \cos \theta + 2i\sin \theta )^{ - 1}}$ is ${1 \over 5}$ for $\theta \in (0,\pi )$, then the value of the integral $\int_0^\theta {\sin x} dx$ is equal to:
Let $z_1, z_2$ and $z_3$ be three complex numbers on the circle $|z|=1$ with $\arg(z_1)=-\frac{\pi}{4}$, $\arg(z_2)=0$ and $\arg(z_3)=\frac{\pi}{4}$. If $\left|\,z_1\overline{z_2}+z_2\overline{z_3}+z_3\overline{z_1}\,\right|^2=\alpha+\beta\sqrt{2}$, $\alpha,\beta\in\mathbb{Z}$, then the value of $\alpha^2+\beta^2$ is:
If a and b are real numbers such that ${\left( {2 + \alpha } \right)^4} = a + b\alpha$ where $\alpha = {{ - 1 + i\sqrt 3 } \over 2}$ then a + b is equal to :
If $z_1,z_2,z_3\in\mathbb{C}$ are the vertices of an equilateral triangle whose centroid is $z_0$, then $\displaystyle \sum_{k=1}^{3}(z_k-z_0)^2$ is equal to
Let n denote the number of solutions of the equation z2 + 3$\overline z $ = 0, where z is a complex number. Then the value of $\sum\limits_{k = 0}^\infty {{1 \over {{n^k}}}} $ is equal to :
If the four complex numbers $z,\overline z ,\overline z - 2{\mathop{\rm Re}\nolimits} \left( {\overline z } \right)$ and $z-2Re(z)$ represent the vertices of a square ofside 4 units in the Argand plane, then $|z|$ is equal to :
For $z \in \mathbb{C}$ if the minimum value of $\lvert z - 3\sqrt{2}\rvert + \lvert z - p\sqrt{2}i\rvert$ is $5\sqrt{2}$, then a value of $p$ is ________.
Let the curve $z(1+i)+\overline{z}(1-i)=4,\ z\in\mathbb{C}$, divide the region $|z-3|\le 1$ into two parts of areas $\alpha$ and $\beta$. Then $|\alpha-\beta|$ equals:
Let $O$ be the origin and $A$ be the point $z_1 = 1 + 2i$. If $B$ is the point $z_2$, $\mathrm{Re}(z_2) < 0$, such that $OAB$ is a right-angled isosceles triangle with $OB$ as hypotenuse, then which of the following is NOT true?
A complex number $z$ is said to be unimodular if $|z|=1$. Suppose $z_{1}$ and
$z_{2}$ are complex numbers such that $\dfrac{z_{1}-2z_{2}}{2-z_{1}\overline{z_{2}}}$ is unimodular and
$z_{2}$ is not unimodular. Then the point $z_{1}$ lies on a :
If the center and radius of the circle $\left|\dfrac{z-2}{z-3}\right|=2$ are respectively $(\alpha,\beta)$ and $\gamma$, then $3(\alpha+\beta+\gamma)$ is equal to:
Let $\left|\frac{\bar{z}-i}{2 \bar{z}+i}\right|=\frac{1}{3}, z \in C$, be the equation of a circle with center at $C$. If the area of the triangle, whose vertices are at the points $(0,0), C$ and $(\alpha, 0)$ is 11 square units, then $\alpha^2$ equals: