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JEE MAIN Previous Year Questions (PYQs)

JEE MAIN Area Enclosed Between The Curves Definite Integration PYQ


JEE MAIN PYQ
The integral $\displaystyle \int_{0}^{\pi}\sqrt{1+4\sin^{2}\frac{x}{2}-4\sin\frac{x}{2}}\,dx$ equals:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2014 (Offline) PYQ

Solution


JEE MAIN PYQ
The area of the region described by $A=\{(x,y):x^{2}+y^{2}\le 1 \text{ and } y^{2}\le 1-x\}$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2014 (Offline) PYQ

Solution


JEE MAIN PYQ
If the area (in sq. units) bounded by the parabola $y^{2}=4\lambda x$ and the line $y=\lambda x,\ \lambda>0$, is $\dfrac{1}{9}$, then $\lambda$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (12 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region given by $\{(x,y):\, xy\le 8,\ 1\le y\le x^{2}\}$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (1 February Evening Shift) PYQ

Solution


JEE MAIN PYQ
If the area of the region $\left\{(x, y):-1 \leq x \leq 1,0 \leq y \leq \mathrm{a}+\mathrm{e}^{|x|}-\mathrm{e}^{-x}, \mathrm{a}>0\right\}$ is $\frac{\mathrm{e}^2+8 \mathrm{e}+1}{\mathrm{e}}$, then the value of $a$ is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (23 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
A line passing through the point $A(-2,0)$ touches the parabola $P: y^2=x-2$ at the point $B$ in the first quadrant. The area of the region bounded by the line $\overline{AB}$, parabola $P$ and the $x$-axis is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (4 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
$ \text{The area bounded by the curves } y=\lvert x^{2}-1\rvert \text{ and } y=1 \text{ is :}$





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (26 July Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area (in square units) bounded by the curves $y=\sqrt{x}$, $2y-x+3=0$, $x$-axis, and lying in the first quadrant is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2013 (Offline) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region bounded by the curve $x^2=4y$ and the straight line $x=4y-2$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (11 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region ${(x,y)\in \mathbb{R}^{2} : x \ge 0,\ y \ge 0,\ y \ge x-2 \text{ and } y \le \sqrt{x}}$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2018 (15 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area bounded by the curves $y=\lvert x-1\rvert+\lvert x-2\rvert$ and $y=3$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (6 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region enclosed by $y\le 4x^{2}$, $x^{2}\le 9y$ and $y\le 4$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (27 July Evening Shift) PYQ

Solution


JEE MAIN PYQ
If the area of the region bounded by the curves $y = 4 - \dfrac{x^2}{4}$ and $y = \dfrac{x-4}{2}$ is equal to $\alpha$, then $6\alpha$ equals





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (7 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region ${(x, y) : x^2 + 4x + 2 \le y \le |x + 2|}$ is equal to





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (24 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) in the first quadrant bounded by the parabola $y=x^{2}+1$, the tangent to it at the point $(2,5)$ and the coordinate axes is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (11 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
If the area of the region ${(x,y):, 1+x^2 \le y \le \min{x+7,; 11-3x}}$ is $A$, then $3A$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (7 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region enclosed by the curves $y=\mathrm{e}^x, y=\left|\mathrm{e}^x-1\right|$ and $y$-axis is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (24 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area enclosed between the curves $y=x|x|$ and $y=x-|x|$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (5 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
$ \text{The area enclosed by the curves } y=\log_{e}(x+e^{2}),; x=\log_{e}!\left(\dfrac{2}{y}\right) \text{ and } x=\log_{e}2,\ \text{above the line } y=1,\ \text{is:} $





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (28 July Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $g(x)=\cos x^{2}$, $f(x)=\sqrt{x}$ and $\alpha,\beta\ (\alpha<\beta)$ be the roots of the quadratic equation $18x^{2}-9\pi x+\pi^{2}=0$. Then the area (in sq. units) bounded by the curve $y=(g\circ f)(x)$ and the lines $x=\alpha$, $x=\beta$ and $y=0$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2018 (Offline) PYQ

Solution


JEE MAIN PYQ
Let the area of the region enclosed by the curves $y=3x$, $2y=27-3x$ and $y=3x-x\sqrt{x}$ be $A$. Then $10A$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (6 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region bounded by the parabola $y=x^{2}+2$ and the lines $y=x+1$, $x=0$ and $x=3$, is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (12 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region

$\left\{(x, y):|x-1| \leq y \leq \sqrt{5-x^{2}}\right\}$ is equal to :






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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (29 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region ${(x,y): 0\le y\le 2|x|+1,; 0\le y\le x^{2}+1,; |x|\le 3}$ is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (28 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region bounded by the curves $x(1+y^{2})=1$ and $y^{2}=2x$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (28 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
Area (in sq. units) of the region outside $\frac{|x|}{2} + \frac{|y|}{3} = 1$ and inside the ellipse $\frac{x^2}{4}$ + $\frac{y^2}{9} = 1$ is \[ 2x - y + 2z = 2 \] \[ x - 2y + \lambda z = -4 \] \[ x + \lambda y + z = 4 \] has no solution. Then the set $S$ :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2 September 2020 (Morning) PYQ

Solution


JEE MAIN PYQ
If the area of the region $\left\{(x, y): \frac{\mathrm{a}}{x^2} \leq y \leq \frac{1}{x}, 1 \leq x \leq 2,0<\mathrm{a}<1\right\}$ is $\left(\log _{\mathrm{e}} 2\right)-\frac{1}{7}$ then the value of $7 \mathrm{a}-3$ is equal to





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (6 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area enclosed by the curves $y^2 + 4x = 4$ and $y - 2x = 2$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (24 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
Area of the region \[ \{(x, y) : x^2 + (y - 2)^2 \le 4, \; x^2 \ge 2y\} \] is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (11 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region $A={(x,y)\in\mathbb{R}\times\mathbb{R}\mid 0\le x\le3,\ 0\le y\le4,\ y\le x^2+3x}$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (8 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region ${(x,y): x\ge 0,\ x+y\le 3,\ x^{2}\le 4y\ \text{and}\ y\le 1+\sqrt{x}}$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2017 (Offline) PYQ

Solution


JEE MAIN PYQ
Consider a region R = {(x, y) $ \in $ R : x2 $ \le $ y $ \le $ 2x}. if a line y = $\alpha $ divides the area of region R intotwo equal parts, then which of the following istrue?





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2 September 2020 (Evening) PYQ

Solution


JEE MAIN PYQ
The area (in square units) of the region bounded by the parabola $y^{2}=4(x-2)$ and the line $y=2x-8$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (30 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the smaller portion enclosed between the curves $x^2 + y^2 = 4$ and $y^2 = 3x$, is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2017 (8 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region

{ (x, y) : 0 $ \le $ y $ \le $ x2 + 1, 0 $ \le $ y $ \le $ x + 1, ${1 \over 2}$ $ \le $ x $ \le $ 2 } is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 3 September 2020 (Morning) PYQ

Solution


JEE MAIN PYQ
Let $S(\alpha)={(x,y):, y^{2}\le x,\ 0\le x\le \alpha}$ and $A(\alpha)$ be the area of the region $S(\alpha)$. If for a $\lambda$, $0<\lambda<4$, $A(\lambda):A(4)=2:5$, then $\lambda$ equals:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (8 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
$ \text{The area of the region enclosed by the curve } y=x^{3} \text{ and its tangent at the point } (-1,-1) \text{ is: } $





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (12 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region enclosed by the curve $f(x)=\max\{\sin x,\cos x\},\ -\pi \le x \le \pi$ and the $x$-axis is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (13 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region S = {(x, y) : y2 $\le$ 8x, y $\ge$ $\sqrt2$x, x $\ge$ 1} is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (28 June Morning Shift) PYQ

Solution


JEE MAIN PYQ
The parabola $y^{2}=4x$ divides the area of the circle $x^{2}+y^{2}=5$ in two parts. The area of the smaller part is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (9 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the part of the circle x2 + y2 = 36, which is outside the parabola y2 = 9x, is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (24 February Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region $A = {(x, y) : x^2 \le y \le x + 2}$ is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (9 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area of the bounded region enclosed by the curve $y = 3 - \left| {x - {1 \over 2}} \right| - |x + 1|$ and the x-axis is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (28 June Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region $\Big\{(x,y): y^{2}\le4x,\ x<4,\ \dfrac{xy(x-1)(x-2)}{(x-3)(x-4)}>0,\ x\ne3\Big\}$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (31 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region $\{(x,y): x^2 \le y \le |x^2-4|,\ y \ge 1\}$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (13 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
Let $\Delta$ be the area of the region $\{(x,y)\in\mathbb{R}^{2}:\ x^{2}+y^{2}\le 21,\ y^{2}\le 4x,\ x\ge 1\}$. Then $\dfrac{1}{2}\Big(\Delta-21\sin^{-1}\!\dfrac{2}{\sqrt{7}}\Big)$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (29 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region $ {(x,y) : y^{2} \ge 2x \ \text{and} \ x^{2} + y^{2} \le 4x,\ x \ge 0,\ y \ge 0} $ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2016 (Offline) PYQ

Solution


JEE MAIN PYQ
Let $$A=\{(x,y)\in\mathbb{R}^{2}:\ y\ge 0,\ 2x\le y\le \sqrt{4-(x-1)^{2}}\}$$ and $$B=\{(x,y)\in\mathbb{R}\times\mathbb{R}:\ 0\le y\le \min\{2x,\ \sqrt{4-(x-1)^{2}}\}\}.$$ Then the ratio of the area of $A$ to the area of $B$ is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (29 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area enclosed by y2 = 8x and y = $\sqrt2$ x that lies outside the triangle formed by y = $\sqrt2$ x, x = 1, y = 2$\sqrt2$, is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (29 June Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region enclosed by the parabolas $y=4x-x^{2}$ and $3y=(x-4)^{2}$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (31 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region \[ A=\{(x,y): |\,\cos x - \sin x\,| \le y \le \sin x,\; 0 \le x \le \tfrac{\pi}{2}\} \] is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (29 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region, inside the circle $ (x - 2\sqrt{3})^2 + y^2 = 12 $ and outside the parabola $ y^2 = 2\sqrt{3}x $, is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (22 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area, enclosed by the curves $y = \sin x + \cos x$ and $y = \left| {\cos x - \sin x} \right|$ and the lines $x = 0,x = {\pi \over 2}$, is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2021 (1 September Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region described by $A = {(x,y)\mid y \ge x^{2} - 5x + 4,\ x + y \ge 1,\ y \le 0}$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2016 (9 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) bounded by the parabola $y=x^{2}-1$, the tangent at the point $(2,3)$ to it, and the $y$–axis is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (9 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area enclosed by the curves $xy+4y=16$ and $x+y=6$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (1 February Morning Shift) PYQ

Solution


JEE MAIN PYQ
Let $q$ be the maximum integral value of $p$ in $[0,10]$ for which the roots of the equation $x^{2}-px+\dfrac{5}{4}p=0$ are rational. Then the area of the region $\left\{(x,y): 0\le y\le (x-q)^{2},\ 0\le x\le q\right\}$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2023 (30 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region ${(x,y): |x-y|\le y \le 4\sqrt{x}}$ is





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (3 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region given by

$A=\left\{(x, y): x^{2} \leq y \leq \min \{x+2,4-3 x\}\right\}$ is :






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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (25 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region bounded by the curves $y=2^{x}$ and $y=|x+1|$, in the first quadrant, is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (10 April Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region $A=\{(x,y): 0\le y\le x|x|+1 \text{ and } -1\le x\le 1\}$ (in sq. units) is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (9 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area of the region enclosed by the curves $y=x^2-4 x+4$ and $y^2=16-8 x$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2025 (22 January Evening Shift) PYQ

Solution


JEE MAIN PYQ
The area (in sq. units) of the region described by $\{(x,y):y^{2}\le 2x \text{ and } y\ge 4x-1\}$ is :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2015 (Offline) PYQ

Solution


JEE MAIN PYQ
One of the points of intersection of the curves $y=1+3x-2x^2$ and $y=\dfrac{1}{x}$ is $\left(\dfrac{1}{2},\,2\right)$. Let the area of the region enclosed by these curves be $\dfrac{1}{24}\big(l\sqrt{5}+m\big)-n\ln(1+\sqrt{5})$, where $l,m,n\in\mathbb{N}$. Then $l+m+n$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2024 (4 April Morning Shift) PYQ

Solution


JEE MAIN PYQ
If the area enclosed between the curves $y = kx^2$ and $x = ky^2$, $(k > 0)$, is $1$ square unit, then $k$ is:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (10 January Morning Shift) PYQ

Solution


JEE MAIN PYQ
The odd natural number $a$, such that the area of the region bounded by $y=1$, $y=3$, $x=0$, $x=y^{a}$ is $\dfrac{364}{3}$, is equal to :





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2022 (26 July Morning Shift) PYQ

Solution


JEE MAIN PYQ
If the area (in sq. units) of the region ${(x,y):, y^{2}\le 4x,; x+y\le 1,; x\ge 0,; y\ge 0}$ is $a\sqrt{2}+b$, then $a-b$ is equal to:





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JEE MAIN JEE Mains PYQ JEE MAIN JEE Main 2019 (12 April Morning Shift) PYQ

Solution



JEE MAIN


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