1
A-II, B-III, C-I, D-IV 2
A-III, B-IV, C-II, D-I 3
A-IV, B-III, C-II, D-I 4
A-IV, B-III, C-I, D-II Go to Discussion
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Solution Dog causes Rabies, Mosquito causes Malaria → A-IV
Amnesia affects Memory, Paralysis affects Movement → B-III
Meningitis affects Brain, Cirrhosis affects Liver → C-II
Influenza is caused by Virus, Typhoid is caused by Bacteria → D-I
Correct matching: A-IV, B-III, C-II, D-I
Qus : 2
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3
If each of $n$ numbers $x_i = i$ is replaced by $(i+1)x_i$, then the new mean is
1
$\dfrac{(n+1)(n+2)}{n}$ 2
$n+1$ 3
$\dfrac{(n+1)(n+2)}{3}$ 4
$\dfrac{(n+1)(5n+4)}{6}$ Go to Discussion
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Solution Original numbers: $1,2,3,\dots,n$
New values:
$(i+1)i = i^2+i$
Sum of new values:
$\sum i^2 + \sum i = \dfrac{n(n+1)(2n+1)}{6} + \dfrac{n(n+1)}{2}$
$= \dfrac{n(n+1)(2n+1+3)}{6}
= \dfrac{n(n+1)(2n+4)}{6}
= \dfrac{n(n+1)(n+2)}{3}$
New mean:
$\dfrac{(n+1)(n+2)}{3}$
Qus : 5
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2
Which of the following are true:
(A) Ogive graph is used to measure the median of the collection of datas.
(B) Two events A and B are such that P(A) = 1/2 and P(B) = 7/12 and P(not A not B) = 1/4 then A and B are
independent events.
(C) Relation for mean, mode and median is given by Mode = 3 Median – 2 Mean.
(D) The number of two–digits even number formed from digits 1,2,3,4,5 is 10
Choose the correct answer from the options given below:
1
(A) and (B) only 2
(A), (C) and (D) Only 3
(C) and (D) Only 4
(B) and (C) Only Go to Discussion
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Solution
Solution:
(A) Ogive is used to determine the Median . ✅ True
(B) Given:
\( P(A \cup B) = 1 - \tfrac{1}{4} = \tfrac{3}{4} \)
So, A and B are not independent. ❌ False
(C) Empirical relation:
\[
\text{Mode} = 3 \times \text{Median} - 2 \times \text{Mean}
\]
✅ True
(D) Two–digit even numbers from {1,2,3,4,5}:True (with repetition allowed)
✔ Final Answer: (A), (C), and (D) are correct.
Qus : 8
CUET PG MCA PYQ
2
Given the marks of 25 students in the class as $\{m_1,m_2,m_3,..m_{25}\}$. Marks lie in the
range of [1-100] and $\overline{m}$ is the mean. Which of the following quantity has the value
zero?
1
$$\sum ^{25}_{i=1}|{{m}}_i-\overline{m}|$$ 2
$$\sum ^{25}_{i=1}\Bigg{(}{{m}}_i-\overline{m}\Bigg{)}$$ 3
$$\sum ^{25}_{i=1}{\Bigg{(}{{m}}_i-\overline{m}\Bigg{)}}^2$$ 4
$$\sum ^{25}_{i=1}\frac{{{m}}_i}{\overline{m}}$$ Go to Discussion
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Solution [{"qus_id":"11478","year":"2022"},{"qus_id":"11480","year":"2022"},{"qus_id":"11674","year":"2024"},{"qus_id":"11712","year":"2024"},{"qus_id":"16658","year":"2023"},{"qus_id":"16681","year":"2023"},{"qus_id":"16712","year":"2023"},{"qus_id":"16728","year":"2023"}]
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