The given series:
$$3, \; 10, \; 27, \; 4, \; 16, \; 64, \; 5, \; 25, \; 125 $$
We notice the pattern should be in triplets:
\[ n, \; n^2, \; n^3 \]
For \(n = 3\): \((3, 9, 27)\) but the series has \(10\) instead of \(9\).
For \(n = 4\): \((4, 16, 64)\) ✓
For \(n = 5\): \((5, 25, 125)\) ✓
Thus, the wrong term is:
\[ \boxed{10} \]
Series: 2, 7, 27, 107, 427, ?
Step 1: Look at the pattern.
Each term seems to follow:
$$a_{n+1} = 4 \times a_n - 1$$
Step 2: Verify the rule.
• 2 → 4×2 - 1 = 7 ✅
• 7 → 4×7 - 1 = 27 ✅
• 27 → 4×27 - 1 = 107 ✅
• 107 → 4×107 - 1 = 427 ✅
Step 3: Find the next term.
• 427 → 4×427 - 1 = 1707 ✅
Missing Term: 1707
Answer: Option 2
| 72 | 24 | 6 |
| 96 | 16 | 12 |
| 108 | ? | 18 |
Grid (row-wise):
(72, 24, 6) (96, 16, 12) (108, ?, 18)
Pattern: In each row, $$\text{third} = 2 \times \frac{\text{first}}{\text{second}}$$
Check Row 1: \( 2 \times \frac{72}{24} = 2 \times 3 = 6 \) ✅
Check Row 2: \( 2 \times \frac{96}{16} = 2 \times 6 = 12 \) ✅
Apply to Row 3: Let the missing number be \(x\). $$18 = 2 \times \frac{108}{x} $$
$$\;\Rightarrow\;18= \frac{216}{x} $$
$$\;\Rightarrow\; x = \frac{216}{18} = 12$$
Missing Number: 12
Answer: Option 1
Given Series: 7, 14, 28, ...
Pattern: Each term is multiplied by 2.
Formula for the nth term: Tn = 7 × 2n-1
T10 = 7 × 210-1 = 7 × 29 = 7 × 512 = 3584
The 10th term is 3584.
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and More.