Aspire's Library
A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations
Study Stuff for MCA Examinations
CUET PG MCA Previous Year Questions (PYQs)
CUET PG MCA Circle PYQ
CUET PG MCA PYQ
Go to Discussion
CUET PG MCA Previous Year PYQ CUET PG MCA CUET 2025 PYQ
The center and radius for the circle $x^2 + y^2 +6x-4y +4 = 0$ respectively are:
1. (2, 3) and 3
2. (3, 2) and 8
3. (2, -3) and 3
4. (-3, 2) and 3
Go to Discussion
CUET PG MCA Previous Year PYQ CUET PG MCA CUET 2025 PYQ
Solution
Solution
Equation: $$x^2 + y^2 + 6x - 4y + 4 = 0$$
Step 1: Group terms.
$$(x^2 + 6x) + (y^2 - 4y) + 4 = 0$$
Step 2: Complete the square.
- For $x^2 + 6x$: add and subtract $(\tfrac{6}{2})^2 = 9$
- For $y^2 - 4y$: add and subtract $(\tfrac{-4}{2})^2 = 4$
$$(x^2 + 6x + 9) + (y^2 - 4y + 4) + 4 - 9 - 4 = 0$$ $$\Rightarrow (x+3)^2 + (y-2)^2 - 9 = 0$$ $$\Rightarrow (x+3)^2 + (y-2)^2 = 9$$
Center: (-3, 2)
Radius: 3
Answer: Option 4
CUET PG MCA PYQ
Go to Discussion
CUET PG MCA Previous Year PYQ CUET PG MCA CUET 2024 PYQ
The equation of a circle that passes through the points (3, 0) and (0, –2) and its lies on a line 2x + 3y = 3 then equation of the cicle is given by:
Go to Discussion
CUET PG MCA Previous Year PYQ CUET PG MCA CUET 2024 PYQ
Solution
CUET PG MCA
Online Test Series,
Information About Examination,
Syllabus, Notification
and More.
View More
CUET PG MCA
Online Test Series,
Information About Examination,
Syllabus, Notification
and More.
View More
Ask Your Question or Put Your Review.
