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MAH CET MCA Parabola PYQ

MAH CET MCA PYQ
The equation of a parabola is $y^2=4x$. Which of the following points lies on the parabola?





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MAH CET MCA Previous Year PYQ MAH CET MCA MAH MCA CET 2025 (Shift 1) PYQ

Solution

For $y^2=4x$, we need $x=\dfrac{y^2}{4}$. For $y=\pm4$, $x=\dfrac{16}{4}=4$ $\Rightarrow$ $(4,4)$ and $(4,-4)$ satisfy. Others give $x\neq\dfrac{y^2}{4}$.

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