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MAH CET MCA Previous Year Questions (PYQs)

MAH CET MCA C Programming Language PYQ

MAH CET MCA PYQ
What is the purpose of the 'break' statement in C?





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MAH CET MCA Previous Year PYQ MAH CET MCA MAH MCA CET 2024 PYQ

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MAH CET MCA PYQ
______ are used to compare two quantities and, depending on their relation, take certain decisions for that comparison.





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MAH CET MCA Previous Year PYQ MAH CET MCA MAH MCA CET 2024 PYQ

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MAH CET MCA PYQ
What will be the output of the following C code?

 #include<stdio.h>  
 int main() 
{     
int x = 10, y = 20;     
int z = x;    
x = y;    
y = z;     
printf("%d %d", x, y);     
return 0; 
 }





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MAH CET MCA Previous Year PYQ MAH CET MCA MAH MCA CET 2024 PYQ

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MAH CET MCA PYQ
What is the output of the below program? 
int main() 
{     
int a, b, sum;     
sum = 0;     
for (a = 0; a < 5; a++) 
{         
for (b = 0; b < 5; b++) 
{             
sum++;         
}    
}     
printf("%d", sum);     
return 0; 
 }






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MAH CET MCA Previous Year PYQ MAH CET MCA MAH MCA CET 2024 PYQ

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MAH CET MCA PYQ
What is the correct syntax for declaring a variable in C?





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MAH CET MCA Previous Year PYQ MAH CET MCA MAH MCA CET 2024 PYQ

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MAH CET MCA PYQ
What will be the value of x so that "Kavita" will be printed? 
 main() 
{     
int x;     
if (x > 4) 
printf("Manisha");     
else 
printf("Kavita"); 
 }





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MAH CET MCA Previous Year PYQ MAH CET MCA MAH MCA CET 2024 PYQ

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MAH CET MCA PYQ
Library function getch() belongs to which header file in C language?





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MAH CET MCA Previous Year PYQ MAH CET MCA MAH MCA CET 2024 PYQ

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MAH CET MCA PYQ
Which of the following is a correct way to declare a variable in C?





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MAH CET MCA Previous Year PYQ MAH CET MCA MAH MCA CET 2025 (Shift 1) PYQ

Solution

In C language, variable declaration syntax is datatype variable_name;. Hence, the correct declaration is int x;.
MAH CET MCA PYQ
#include <stdio.h>
int main() {
    printf("%d", 5 + 3 * 2);
    return 0;
}





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MAH CET MCA Previous Year PYQ MAH CET MCA MAH MCA CET 2025 (Shift 1) PYQ

Solution

According to the precedence of operators, multiplication (*) is evaluated before addition (+). So, $5 + 3 * 2 = 5 + 6 = 11$.

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