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NIMCET Previous Year Questions (PYQs)

NIMCET Percentages PYQ

NIMCET PYQ
A number which, when increased by 15% becomes 161. What is the original number?





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NIMCET Previous Year PYQ NIMCET NIMCET 2025 PYQ

Solution

Let the original number = x

Increased by 15% ⇒ New value = 1.15x

Given: 1.15x = 161

x = 161 ÷ 1.15

x = 140

✅ Final Answer: The original number is 140.

NIMCET PYQ
In a city, 40.1% of the adults are illiterate while 85.1% of the children are literate. If the ratio of the adults to that of the children is 2:3, then what percent of the population is literate?





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NIMCET Previous Year PYQ NIMCET NIMCET 2020 PYQ

Solution

Let total population be $100$ (as given). Ratio of adults : children $= 2 : 3$ 
So, total parts $= 2 + 3 = 5$ 
Adults $= \dfrac{2}{5} \times 100 = 40$ 
Children $= \dfrac{3}{5} \times 100 = 60$ 
Now use literacy data: For adults: Illiterate adults $= 40.1%$ 
So, literate adults $= 100% - 40.1% = 59.9%$ 
Literate adults $= 59.9%$ of $40$ $= \dfrac{59.9}{100} \times 40 = 23.96$ 
For children: Literate children $= 85.1%$ of $60$ $= \dfrac{85.1}{100} \times 60 = 51.06$ 

Total literate population $= 23.96 + 51.06 = 75.02$ 

Since total population is $100$, 
Literate percentage $= 75.02% \approx 75%$.
NIMCET PYQ
In a competitive examination in Maharashtra state 9% candidates got selected from the total appeared candidates. Tripura state had an equal number of candidates appeared and 12% candidates got selected with 102 more candidates got selected than Maharashtra state. What was the number of candidates appeared from each state?





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NIMCET Previous Year PYQ NIMCET NIMCET 2020 PYQ

Solution

Let the number of candidates appeared from each state be $x$. 
Maharashtra selected candidates $= 9\%$ of $x = \dfrac{9}{100}x$ 

 Tripura selected candidates $= 12\%$ of $x = \dfrac{12}{100}x$ 

 Given that Tripura has $102$ more selected candidates than Maharashtra: \[ \dfrac{12}{100}x - \dfrac{9}{100}x = 102 \] \[ \dfrac{3}{100}x = 102 \] \[ x = 102 \times \dfrac{100}{3} = 3400 \] 
Thus, the number of candidates appeared from each state is 3400.
NIMCET PYQ
Shiva gave 40% of his monthly salary to his mother from the remaining he used 7% for electronic gadgets and 23% he kept aside for his monthly expenses. The remaining amount he transferred to his friend’s account. The sum of the amount he gave to his mother and he transferred to his friend account was 41000. What was Shiva’s monthly salary?





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NIMCET Previous Year PYQ NIMCET NIMCET 2020 PYQ

Solution

Let Shiva's monthly salary be $x$.

He gave $40%$ of his salary to his mother:
Amount to mother $= 40%$ of $x = 0.40x$.

Remaining salary after giving to mother:
$= x - 0.40x = 0.60x$.

From this remaining $0.60x$:
He used $7%$ for electronic gadgets:
Amount for gadgets $= 7%$ of $0.60x = 0.07 \times 0.60x = 0.042x$.

He kept $23%$ for monthly expenses:
Amount for expenses $= 23%$ of $0.60x = 0.23 \times 0.60x = 0.138x$.

Total used from the remaining on gadgets and expenses:
$0.042x + 0.138x = 0.18x$.

So the amount transferred to his friend's account:
$= 0.60x - 0.18x = 0.42x$.

Now, sum of the amount given to his mother and transferred to his friend is given as $41000$:
Amount to mother $+ $ amount to friend $= 0.40x + 0.42x = 0.82x$.
So,
$0.82x = 41000$
$x = \dfrac{41000}{0.82} = 50000$.

Therefore, Shiva's monthly salary is 50000.
NIMCET PYQ
In the half yearly exam only 60% of the students were passed. Out of these (passed in half-yearly) only 70% students are passed in annual exam, out of remaining students (who fail in half-yearly exam) 80% passed in annual exam. What percent of the students passed the annual exam?





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NIMCET Previous Year PYQ NIMCET NIMCET 2023 PYQ

Solution

Given:

  • 60% students passed the half-yearly exam.
  • Of them, 70% passed the annual exam.
  • From the remaining 40% (who failed half-yearly), 80% passed the annual exam.

Assume total students = 100

✅ From 60 students who passed half-yearly:
→ 70% of 60 = 42 passed annual exam.

✅ From 40 students who failed half-yearly:
→ 80% of 40 = 32 passed annual exam.

✅ Total students who passed annual exam = 42 + 32 = 74
Final Answer: 74%

NIMCET PYQ
In an examination, 78% of the total students who appeared were successful. If the total number of failures was 176 and 34% got first class, then how many students got first class?





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NIMCET Previous Year PYQ NIMCET NIMCET 2020 PYQ

Solution

Let the total number of students = N

We know,

  • 78% students were successful → 22% students failed.
  • Number of failures = 176.

So,

22% of N = 176
⇒ 22N / 100 = 176
⇒ N = (176 × 100) / 22 = 800

Total students appeared = 800

Now, 34% got first class:

First class students = 34% of 800
= (34 × 800) / 100
= 272

✅ Final Answer: 272 students got first class.

NIMCET PYQ
If the numerator of a fraction is increased by 25% and denominator decreased by 20%, the new value is 5/4. What is the original value?





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NIMCET Previous Year PYQ NIMCET NIMCET 2020 PYQ

Solution

Let the original fraction be N/D.

According to the problem:

  • Numerator is increased by 25% → New numerator = 1.25N
  • Denominator is decreased by 20% → New denominator = 0.8D

So, new fraction =
(1.25N) / (0.8D) = 5/4

Simplify:
(1.25 / 0.8) × (N/D) = 5/4
(1.25 ÷ 0.8) = 1.5625 = 25/16

⇒ (25/16) × (N/D) = 5/4

⇒ N/D = (5/4) × (16/25)
= 80 / 100
= 4/5

✅ Final Answer: The original fraction = 4/5

NIMCET PYQ
Ritu purchased 20 dozen of bananas at the rate of Rs. 375 per dozen. she sold each one of them at the rate of Rs. 33. What was her profit percentage?





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NIMCET Previous Year PYQ NIMCET NIMCET 2023 PYQ

Solution

 Ritu's Profit Percentage on Bananas

Step 1: Ritu purchased 20 dozen bananas.
Cost per dozen = ₹375

Total cost price (CP) = 20 × 375 = ₹7500

Total number of bananas = 20 × 12 = 240

Selling price (SP) per banana = ₹33

Total SP = 240 × 33 = ₹7920

Step 2: Calculate Profit

Profit = SP − CP = 7920 − 7500 = ₹420

Profit % = (Profit / CP) × 100 = (420 / 7500) × 100 = 5.6%

✅ Final Answer: 5.6%

NIMCET PYQ
Hemant deposits 10% of his salary in PF. He saves 30% of the remaining salary. The ratio of his expense on medicine and groceries is 3:4 of the remaining salary after saving. If his expense on the medicine was Rs. 2700, then find his monthly salary.





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NIMCET Previous Year PYQ NIMCET NIMCET 2023 PYQ

Solution

Hemant's Monthly Salary Calculation

Step 1: Let Hemant's monthly salary be x.

He deposits 10% in PF ⇒ PF = 0.10x

Remaining salary after PF = 0.90x

Step 2: Savings

He saves 30% of the remaining ⇒ Savings = 0.30 × 0.90x = 0.27x

Remaining after savings = 0.90x - 0.27x = 0.63x

Step 3: Expenses on Medicine and Groceries

The ratio is given: Medicine : Groceries = 3 : 4

Total ratio parts = 3 + 4 = 7

Medicine = (3/7) × 0.63x = 0.27x

Step 4: Given that medicine expense = Rs. 2700

0.27x = 2700

⇒ x = 2700 ÷ 0.27 = ₹10,000

✅ Final Answer: ₹10,000

NIMCET PYQ
In the half yearly exam only 60% of the students were passed. 
Out of these (passed in half-yearly) only 70% students are passed in annual exam, out of remaining students (who fail in half-yearly exam) 80% passed in annual exam. What percent of the students passed the annual exam?





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NIMCET Previous Year PYQ NIMCET NIMCET 2024 PYQ

Solution

Percentage Puzzle: Exam Pass Analysis

Step-by-Step Breakdown:

  • Assume total students = 100
  • Passed in Half-Yearly = 60 students
  • 70% of 60 passed in Annual = 42 students
  • Failed in Half-Yearly = 40 students
  • 80% of 40 passed in Annual = 32 students
  • Total passed in Annual = 42 + 32 = 74 students

✅ Final Answer: 74% of the students passed the annual exam.

NIMCET PYQ
The percentage change in area of a rectangle by decreasing its length and increasing its breadth by 5% is





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NIMCET Previous Year PYQ NIMCET NIMCET 2025 PYQ

Solution

Assume: Length = 100, Breadth = 100

Original Area = 100 × 100 = 10,000

New length = 95 (5% decrease)
New breadth = 105 (5% increase)

New Area = 95 × 105 = 9975

Change = 9975 – 10000 = –25

Percentage change = (–25 ÷ 10000) × 100 = –0.25%

✅ Area decreases by 0.25%

NIMCET PYQ
If a number is increased by 30% and then decreased by 20%, what is the net change?





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NIMCET Previous Year PYQ NIMCET NIMCET 2025 PYQ

Solution

Let the original number be $100$.

Increased by $30\%$ ⇒ New value = $100 + 30 = 130$.
Decreased by $20\%$ ⇒ New value = $130 - 20\% \text{ of } 130 = 130 - 26 = 104$.

Net change = $104 - 100 = +4$.
Percentage change = $\dfrac{4}{100} \times 100 = 4\%$.

✅ Final Answer: Net increase of 4%

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