Aspire's Library

A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations
  • MCA NIMCET
    Previous Year Questions

MCA NIMCET Previous Year Questions (PYQs)

MCA NIMCET Rectangular Cartesian Coordinates PYQ

MCA NIMCET PYQ
If the distance of $(x,y)$ from the origin is defined as $d(x,y) = \max(|x|,|y|)$, then the locus of points where $d(x,y)=1$ is:





Go to Discussion
MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2009 PYQ

Solution

$\max(|x|,|y|)=1$ describes a square with vertices $(\pm1,\pm1)$. 
Side length = $2$ 
Area = $4$
MCA NIMCET PYQ
$ABC$ is isosceles with $AB = AC$. $BC$ is parallel to x-axis. $m_1, m_2$ are slopes of the medians from $B$ and $C$. Then:





Go to Discussion
MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2009 PYQ

Solution

Let coordinates: $B(-a, 0)$ $C(a, 0)$ $A(0, h)$ 
 Median from $B$ goes to midpoint of $AC$: $(0, h/2)$ 
Slope: $m_1 = \dfrac{h/2 - 0}{0 - (-a)} = \dfrac{h}{2a}$ 

 Median from $C$ goes to midpoint of $AB$: $(0, h/2)$ 
Slope: $m_2 = \dfrac{h/2 - 0}{0 - a} = -\dfrac{h}{2a}$ 

 Thus: $m_1 + m_2 = 0$
MCA NIMCET PYQ
A line $L$ has intercepts $a$ and $b$ on the coordinate axes. When the axes are rotated through a given angle, keeping the origin fixed, the same line has intercepts $p$ and $q$. Which of the following is true?





Go to Discussion
MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2008 PYQ

Solution

Intercept form of line remains invariant under rotation in terms of reciprocal squares. Answer: $\boxed{\dfrac{1}{a^2}+\dfrac{1}{b^2}=\dfrac{1}{p^2}+\dfrac{1}{q^2}}$
MCA NIMCET PYQ
The point $(4,1)$ undergoes the following transformations successively: (i) Reflection about the line $y=x$ (ii) Translation through a distance $2$ units along the positive $x$-axis (iii) Rotation by an angle $\frac{\pi}{4}$ anticlockwise about the origin The final position of the point is:





Go to Discussion
MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2010 PYQ

Solution

Solution: Step 1: Reflect (4,1) about y=x → (1,4) Step 2: Translate 2 units in +x direction → (1+2, 4) = (3,4) Step 3: Rotate (3,4) by π/4 anticlockwise: New x = (3 - 4)/√2 = -1/√2 New y = (3 + 4)/√2 = 7/√2 Final point = $\left(\frac{-1}{\sqrt{2}}, \frac{7}{\sqrt{2}}\right)$
MCA NIMCET PYQ
If P(1,2), Q(4,6), R(5,7) and S(a,b) are the vertices of a parallelogram PQRS, then 





Go to Discussion
MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2021 PYQ

Solution

MCA NIMCET PYQ
If the points  lie in the region corresponding to the acute angle between the lines and then





Go to Discussion
MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2019 PYQ

Solution


MCA NIMCET PYQ
If (2, 1), (–1, –2), (3, 3) are the midpoints of the sides BC, CA, AB of a triangle ABC, then equation of the line BC is





Go to Discussion
MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2015 PYQ

Solution

MCA NIMCET PYQ
The median AD of ΔABC is bisected at E and BE is produced to meet the side AC at F. Then, AF ∶ FC is





Go to Discussion
MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2014 PYQ

Solution

MCA NIMCET PYQ
A triangle has a vertex at (1, 2) and the mid points of the two sides through it are (-1, 1) and (2, 3). Then the area of this triangle is





Go to Discussion
MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2026 PYQ

Solution

Let vertex be $A(1,2)$. 
Midpoints of sides through $A$ are: 
$M_1(-1,1)$ and $M_2(2,3)$ 

Let other two vertices be $B(x_1,y_1)$ and $C(x_2,y_2)$. 

Using midpoint formula: $\left(\frac{1+x_1}{2},\frac{2+y_1}{2}\right)=(-1,1)$ 
$x_1=-3,\ y_1=0$ 
So, $B(-3,0)$ 

Similarly, $\left(\frac{1+x_2}{2},\frac{2+y_2}{2}\right)=(2,3)$ $x_2=3,\ y_2=4$ 
So, $C(3,4)$ 

Area of triangle: 
$\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|$ 
$=\frac{1}{2}|1(0-4)+(-3)(4-2)+3(2-0)|$ 
$=\frac{1}{2}|-4-6+6|$ 
$=\frac{1}{2}\times 4$ 
$=2$

MCA NIMCET

Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More

MCA NIMCET

Online Test Series,
Information About Examination,
Syllabus, Notification
and More.

Click Here to
View More
Limited Seats
× Aspire MCA Promotion

Game Changer NIMCET Test Series 2026

Boost your preparation with mock tests, analysis and rank-focused practice.

JOIN NOW
Ask Your Question or Put Your Review.

loading...