MCA NIMCET Age Previous Year Question Paper and Solution with PDF

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MCA NIMCET Previous Year Questions (PYQs)

MCA NIMCET Age PYQ

Qus : 1 MCA NIMCET PYQ

The sum of ages of a daughter and mother is 63 yr. Four years back, the mother's age was 4 times that of daughter's age at that time. What is the present age of the mother?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2014 PYQ

Solution

Qus : 2 MCA NIMCET PYQ

Father is aged three times more than the age of his son Rohit. After 8 yr, he would be two and a half of Rohit's age. After further 8 yr, how many times would he be of Rohit's age?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2014 PYQ

Solution

Qus : 3 MCA NIMCET PYQ

A person’s present age is two fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. What is the present age of his mother?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2020 PYQ

Solution

Present Age of the Mother

Let mother’s present age = $M$, person’s present age = $P$.
Given:
$P = \frac{2}{5} M$ ...(1)
After 8 years:
$P + 8 = \frac{1}{2} (M + 8)$ ...(2)

Substitute $P$ from (1) into (2):
\[ \frac{2}{5}M + 8 = \frac{1}{2}(M + 8) \] Multiply both sides by 10 to clear denominators:
\[ 4M + 80 = 5M + 40 \] \[ 80 - 40 = 5M - 4M \] \[ 40 = M \]

Answer: The mother’s present age is 40 years

Qus : 4 MCA NIMCET PYQ

Ajith is three times older than Babita. Chetu is half the age of Das. Babita is older than Chetu. Which of the following additional information is needed to estimate the age of Ajith?

I. Chetu is 10 yr old.

II. Both Babita and Das are older than Chetu by the same number of years.

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2014 PYQ

Solution

Qus : 5 MCA NIMCET PYQ

Sum of ages of Anu and Bhanu is 10 years more than the sum of ages of Bhanu, Chanu, and Dhanu. The average age of Chanu and Dhanu is 19 years. Find the average age of Anu and Dhanu if Dhanu is 10 years elder than Chanu.

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2020 PYQ

Solution

Average Age of Anu and Dhanu

Let the ages be:
Anu = $A$, Bhanu = $B$, Chanu = $C$, Dhanu = $D$

Given:
1) $A + B = 10 + B + C + D \Rightarrow A = 10 + C + D$
2) Average age of Chanu and Dhanu = 19
$\Rightarrow \frac{C + D}{2} = 19 \Rightarrow C + D = 38$
3) Dhanu is 10 years elder than Chanu:
$D = C + 10$

Substitute $D$ in $C + D = 38$:
\[ C + (C + 10) = 38 \Rightarrow 2C = 28 \Rightarrow C = 14 \] \[ D = 14 + 10 = 24 \]

Now, $A = 10 + C + D = 10 + 14 + 24 = 48$

Average age of Anu and Dhanu:
\[ \frac{A + D}{2} = \frac{48 + 24}{2} = \frac{72}{2} = 36 \]

Answer: The average age of Anu and Dhanu is 36 years.

Qus : 6 MCA NIMCET PYQ

Rakesh says to Mahesh, “I am as old as you were when I was one-third as old as you are.” If the sum of their ages is 60 years, find the present age of Mahesh (in years).

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2023 PYQ

Solution

\[ \text{Let Rakesh's age} = R,\] \[ \text{Mahesh's age} = M \] \[ R + M = 60 \quad \cdots (i) \] From the statement: Rakesh says, "I am as old as you were when I was one–third as old as you are." That means: when Rakesh was $ \tfrac{1}{3}M $, Mahesh's age was $ R $. So, time passed: \[ R - \tfrac{1}{3}M \] Then Mahesh's age at that time: \[ M - (R - \tfrac{1}{3}M) = R \quad \cdots (ii) \] Now solve equation (ii): \[ M - R + \tfrac{1}{3}M = R \] \[ \tfrac{4}{3}M = 2R \] \[ 2M = 3R \quad \Rightarrow \quad M = \tfrac{3}{2}R \] Substitute in (i): \[ R + \tfrac{3}{2}R = 60 \] \[ \tfrac{5}{2}R = 60 \quad \Rightarrow \quad R = 24 \] \[ M = \tfrac{3}{2} \times 24 = 36 \] \[ \boxed{\text{Mahesh's present age = 36 years}} \]

Qus : 7 MCA NIMCET PYQ

Reena met Natasha’s children. Rahul said, “The square of my age plus the cube of my sister’s age is 7148.” Preeti said, “The square of my age plus the cube of his age is 5274.”

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2009 PYQ

Solution

Let Rahul = R, Preeti = P

Check option 4: R = 17, P = 19

17² + 19³ = 289 + 6859 = 7148 ✔

19² + 17³ = 361 + 4913 = 5274 ✔

This matches both statements.

Qus : 8 MCA NIMCET PYQ

Pushpa is twice as old as Rita was two years ago. If the difference between their ages is $2$ years, how old is Pushpa today?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2011 PYQ

Solution

Let Pushpa $=P$, Rita $=R$. $ P - R = 2 $ Given: $ P = 2(R - 2) $ Substitute $P = R + 2$: $ R + 2 = 2R - 4 $ $ R = 6 $ So $ P = R + 2 = 8 $

Qus : 9 MCA NIMCET PYQ

In which year was Arjun born? Arjun at present is 25 years younger to his mother. Arjun’s brother, who was born in 1964, is 35 years younger to his mother.

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2024 PYQ

Solution

Given:

Arjun is 25 years younger than his mother.
Arjun’s brother was born in 1964 and is 35 years younger than their mother.

We want: Arjun’s birth year.

Step 1: Calculate the mother's birth year:

\[ 1964 + 35 = 1999 \] So, the mother was born in 1999.

Step 2: Arjun is 25 years younger than his mother:

\[ 1999 - 25 = 1974 \] Therefore, Arjun was born in 1974.

✅ Final Answer: Arjun was born in 1974

Qus : 10 MCA NIMCET PYQ

The average age of husband and wife was 22 years when they were married five years back. What is the present average age of the family if they have a three year old child?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2011 PYQ

Solution

Five years ago:

Average of husband and wife = 22 ⇒ sum of ages then = 22 × 2 = 44

After 5 years, each becomes 5 years older:

New sum (husband + wife) = 44 + 5 + 5 = 54

Child’s age = 3 ⇒ total of family ages now = 54 + 3 = 57

Average age of family now = 57 ÷ 3 = 19 years

Qus : 11 MCA NIMCET PYQ

There are four brothers Alan, Bob, Carl and Dave. Dave is two years older than Bob. Bob is one year younger than Carl. Alan, who is 34, is two years younger than Carl. Who is the oldest?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2013 PYQ

Solution

Qus : 12 MCA NIMCET PYQ

When Rajeev was born his father was 32 years older than his brother and his mother was 25 years older than his.sister. If Rajeev's brother is 6 years older than Rajeev and his mother is 3 years younger than his father, how old was Rajeev's sister when he was born?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2013 PYQ

Solution

Qus : 13 MCA NIMCET PYQ

A person's present age is two-fifth of the age of his mother. After 8 years, he will be one half of the age of his mother. What is the present age of the mother?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2022 PYQ

Solution

Let present age of mother is x,

then present age of his som = $\frac{2x}{5}$

After 8 year son's age$\frac{2x}{5}+8$

mother's age =$x+8$

And given that son's age is $\frac{1}{2}$ time of mother's

$\frac{2x}{5}+8=\frac{1}{2}(x+8)$

Hence ,present age of mother is 40

Qus : 14 MCA NIMCET PYQ

At an IIM entrepreneurship summit, two young founders - Karan and Deepak - introduced their startup. In their quirky opening, they said: "The product of our ages is 240. And just like in our startup strategy, twice Deepak's age is 4 years more than Karan's age." How old was Deepak two years ago?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2025 PYQ

Solution

Let Karan’s present age = $K$ years
Let Deepak’s present age = $D$ years

Given:
$K \times D = 240$
and $2D = K + 4 \Rightarrow K = 2D - 4$

Substitute in the first equation:
$(2D - 4)D = 240$
$\Rightarrow 2D^2 - 4D - 240 = 0$
$\Rightarrow D^2 - 2D - 120 = 0$

Solving: $D = \dfrac{2 + \sqrt{484}}{2} = \dfrac{2 + 22}{2} = 12$

Deepak’s present age = $12$ years
Two years ago = $12 - 2 = \mathbf{10}$ years

✅ Final Answer: $10$ years

Qus : 15 MCA NIMCET PYQ

Radha is twice as old as Rita was 2 years ago. If difference between their ages is 2 years, how old is Radha today?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2021 PYQ

Solution

Qus : 16 MCA NIMCET PYQ

Ten years ago, Ram was twice as old as Shyam. Ten years from now, the ratio of their ages will be 3:2. What is Ram's present age?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2025 PYQ

Solution

Let Ram’s present age = $R$ years
Let Shyam’s present age = $S$ years

Ten years ago: $R - 10 = 2(S - 10)$
⇒ $R = 2S - 10$

Ten years from now: $\dfrac{R + 10}{S + 10} = \dfrac{3}{2}$
⇒ $2R + 20 = 3S + 30$
⇒ $2R = 3S + 10$

Substitute $R = 2S - 10$ into it:
$2(2S - 10) = 3S + 10$
⇒ $4S - 20 = 3S + 10$
⇒ $S = 30$

Then $R = 2(30) - 10 = 50$

✅ Final Answer: Ram’s present age = 50 years

Qus : 17 MCA NIMCET PYQ

Five years ago, $A$ was three times as old as $B$. Now, $A$ is twice as old as $B$. What is $A$'s current age in years?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2026 PYQ

Solution

Let the present age of $B$ be $x$ years.

Then present age of $A$ is:

$2x$

Five years ago,

Age of $A=2x-5$

Age of $B=x-5$

According to the question:

$2x-5=3(x-5)$

$2x-5=3x-15$

$3x-2x=15-5$

$x=10$

So, present age of $A$ is:

$2x=2(10)=20$

Qus : 18 MCA NIMCET PYQ

My mother is twice as old as my brother. I am five years younger to my brother but three years older to my sister. If my sister is twelve years of age, how old is my mother?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2018 PYQ

Solution

Qus : 19 MCA NIMCET PYQ

John is 20 years older than Steve. In 10 years, Steve's age will be half of that of John. What is the present age of Steve?

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MCA NIMCET Previous Year PYQ MCA NIMCET NIMCET 2017 PYQ

Solution

Let the age of Steve be “x” then the age of John is x + 20 after 10 years Steve age be (x + 10), John's age is x+ 30. Now,

2(x + 10) = x +3

Therefore, x = 10

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MCA NIMCET Previous Year Questions (PYQs)

MCA NIMCET Age PYQ

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Average Age of Anu and Dhanu

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Given:

Step 1: Calculate the mother's birth year:

Step 2: Arjun is 25 years younger than his mother:

Solution

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